Solve by Graphing 2x+y=3 3y=x-12

$2 x + y = 3$ $3 y = x - 12$

Step 1

Subtract $2 x$ from both sides of the equation.

$y = 3 - 2 x$

$3 y = x - 12$

Step 2

Divide each term in $3 y = x - 12$ by $3$ and simplify.

Divide each term in $3 y = x - 12$ by $3$ .

$\frac{3 y}{3} = \frac{x}{3} + \frac{- 12}{3}$

$y = 3 - 2 x$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{x}{3} + \frac{- 12}{3}$

$y = 3 - 2 x$

Divide $y$ by $1$ .

$y = \frac{x}{3} + \frac{- 12}{3}$

$y = 3 - 2 x$

$y = \frac{x}{3} + \frac{- 12}{3}$

$y = 3 - 2 x$

$y = \frac{x}{3} + \frac{- 12}{3}$

$y = 3 - 2 x$

Simplify the right side.

Divide $- 12$ by $3$ .

$y = \frac{x}{3} - 4$

$y = 3 - 2 x$

$y = \frac{x}{3} - 4$

$y = 3 - 2 x$

$y = \frac{x}{3} - 4$

$y = 3 - 2 x$

Step 3

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(3, - 3)$

Step 4