Solve by Graphing 2x+y=3 4x+2y=6

$2 x + y = 3$ $4 x + 2 y = 6$

Step 1

Subtract $2 x$ from both sides of the equation.

$y = 3 - 2 x$

$4 x + 2 y = 6$

Step 2

Subtract $4 x$ from both sides of the equation.

$2 y = 6 - 4 x$

$y = 3 - 2 x$

Step 3

Divide each term in $2 y = 6 - 4 x$ by $2$ and simplify.

Divide each term in $2 y = 6 - 4 x$ by $2$ .

$\frac{2 y}{2} = \frac{6}{2} + \frac{- 4 x}{2}$

$y = 3 - 2 x$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{6}{2} + \frac{- 4 x}{2}$

$y = 3 - 2 x$

Divide $y$ by $1$ .

$y = \frac{6}{2} + \frac{- 4 x}{2}$

$y = 3 - 2 x$

$y = \frac{6}{2} + \frac{- 4 x}{2}$

$y = 3 - 2 x$

$y = \frac{6}{2} + \frac{- 4 x}{2}$

$y = 3 - 2 x$

Simplify the right side.

Simplify each term.

Divide $6$ by $2$ .

$y = 3 + \frac{- 4 x}{2}$

$y = 3 - 2 x$

Cancel the common factor of $- 4$ and $2$ .

Factor $2$ out of $- 4 x$ .

$y = 3 + \frac{2 (- 2 x)}{2}$

$y = 3 - 2 x$

Cancel the common factors.

Factor $2$ out of $2$ .

$y = 3 + \frac{2 (- 2 x)}{2 (1)}$

$y = 3 - 2 x$

Cancel the common factor.

$y = 3 + \frac{2 (- 2 x)}{2 \cdot 1}$

$y = 3 - 2 x$

Rewrite the expression.

$y = 3 + \frac{- 2 x}{1}$

$y = 3 - 2 x$

Divide $- 2 x$ by $1$ .

$y = 3 - 2 x$

Step 4

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$y = - 2 x + 3$

Step 5

Solve by Graphing 2x+y=3 4x+2y=6

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