Solve by Graphing -3X=3-y 2y=6x+6

$- 3 X = 3 - y$ $2 y = 6 x + 6$

Step 1

Rewrite the equation as $3 - y = - 3 X$ .

$3 - y = - 3 X$

$2 y = 6 x + 6$

Step 2

Subtract $3$ from both sides of the equation.

$- y = - 3 X - 3$

$2 y = 6 x + 6$

Step 3

Divide each term in $- y = - 3 X - 3$ by $- 1$ and simplify.

Divide each term in $- y = - 3 X - 3$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 3 X}{- 1} + \frac{- 3}{- 1}$

$2 y = 6 x + 6$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 3 X}{- 1} + \frac{- 3}{- 1}$

$2 y = 6 x + 6$

Divide $y$ by $1$ .

$y = \frac{- 3 X}{- 1} + \frac{- 3}{- 1}$

$2 y = 6 x + 6$

$y = \frac{- 3 X}{- 1} + \frac{- 3}{- 1}$

$2 y = 6 x + 6$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{- 3 X}{- 1}$ .

$y = - 1 \cdot (- 3 X) + \frac{- 3}{- 1}$

$2 y = 6 x + 6$

Rewrite $- 1 \cdot (- 3 X)$ as $- (- 3 X)$ .

$y = - (- 3 X) + \frac{- 3}{- 1}$

$2 y = 6 x + 6$

Multiply $- 3$ by $- 1$ .

$y = 3 X + \frac{- 3}{- 1}$

$2 y = 6 x + 6$

Divide $- 3$ by $- 1$ .

$y = 3 X + 3$

$2 y = 6 x + 6$

$y = 3 X + 3$

$2 y = 6 x + 6$

$y = 3 X + 3$

$2 y = 6 x + 6$

$y = 3 X + 3$

$2 y = 6 x + 6$

Step 4

Divide each term in $2 y = 6 x + 6$ by $2$ and simplify.

Divide each term in $2 y = 6 x + 6$ by $2$ .

$\frac{2 y}{2} = \frac{6 x}{2} + \frac{6}{2}$

$y = 3 X + 3$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{6 x}{2} + \frac{6}{2}$

$y = 3 X + 3$

Divide $y$ by $1$ .

$y = \frac{6 x}{2} + \frac{6}{2}$

$y = 3 X + 3$

$y = \frac{6 x}{2} + \frac{6}{2}$

$y = 3 X + 3$

$y = \frac{6 x}{2} + \frac{6}{2}$

$y = 3 X + 3$

Simplify the right side.

Simplify each term.

Cancel the common factor of $6$ and $2$ .

Factor $2$ out of $6 x$ .

$y = \frac{2 (3 x)}{2} + \frac{6}{2}$

$y = 3 X + 3$

Cancel the common factors.

Factor $2$ out of $2$ .

$y = \frac{2 (3 x)}{2 (1)} + \frac{6}{2}$

$y = 3 X + 3$

Cancel the common factor.

$y = \frac{2 (3 x)}{2 \cdot 1} + \frac{6}{2}$

$y = 3 X + 3$

Rewrite the expression.

$y = \frac{3 x}{1} + \frac{6}{2}$

$y = 3 X + 3$

Divide $3 x$ by $1$ .

$y = 3 x + \frac{6}{2}$

$y = 3 X + 3$

$y = 3 x + \frac{6}{2}$

$y = 3 X + 3$

$y = 3 x + \frac{6}{2}$

$y = 3 X + 3$

Divide $6$ by $2$ .

$y = 3 x + 3$

$y = 3 X + 3$

$y = 3 x + 3$

$y = 3 X + 3$

$y = 3 x + 3$

$y = 3 X + 3$

$y = 3 x + 3$

$y = 3 X + 3$

Step 5

This system is not in terms of $x$ and $y$ therefore it can\'t be solved using the graphing method.

Can\'t graph this system.

Solve by Graphing -3X=3-y 2y=6x+6

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