Solve by Graphing 3x-3y=12 4y-8x=-16

$3 x - 3 y = 12$ $4 y - 8 x = - 16$

Step 1

Subtract $3 x$ from both sides of the equation.

$- 3 y = 12 - 3 x$

$4 y - 8 x = - 16$

Step 2

Divide each term in $- 3 y = 12 - 3 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = 12 - 3 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{12}{- 3} + \frac{- 3 x}{- 3}$

$4 y - 8 x = - 16$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{12}{- 3} + \frac{- 3 x}{- 3}$

$4 y - 8 x = - 16$

Divide $y$ by $1$ .

$y = \frac{12}{- 3} + \frac{- 3 x}{- 3}$

$4 y - 8 x = - 16$

$y = \frac{12}{- 3} + \frac{- 3 x}{- 3}$

$4 y - 8 x = - 16$

$y = \frac{12}{- 3} + \frac{- 3 x}{- 3}$

$4 y - 8 x = - 16$

Simplify the right side.

Simplify each term.

Divide $12$ by $- 3$ .

$y = - 4 + \frac{- 3 x}{- 3}$

$4 y - 8 x = - 16$

Cancel the common factor of $- 3$ .

Cancel the common factor.

$y = - 4 + \frac{- 3 x}{- 3}$

$4 y - 8 x = - 16$

Divide $x$ by $1$ .

$y = - 4 + x$

$4 y - 8 x = - 16$

$y = - 4 + x$

$4 y - 8 x = - 16$

$y = - 4 + x$

$4 y - 8 x = - 16$

$y = - 4 + x$

$4 y - 8 x = - 16$

$y = - 4 + x$

$4 y - 8 x = - 16$

Step 3

Add $8 x$ to both sides of the equation.

$4 y = - 16 + 8 x$

$y = - 4 + x$

Step 4

Divide each term in $4 y = - 16 + 8 x$ by $4$ and simplify.

Divide each term in $4 y = - 16 + 8 x$ by $4$ .

$\frac{4 y}{4} = \frac{- 16}{4} + \frac{8 x}{4}$

$y = - 4 + x$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 y}{4} = \frac{- 16}{4} + \frac{8 x}{4}$

$y = - 4 + x$

Divide $y$ by $1$ .

$y = \frac{- 16}{4} + \frac{8 x}{4}$

$y = - 4 + x$

$y = \frac{- 16}{4} + \frac{8 x}{4}$

$y = - 4 + x$

$y = \frac{- 16}{4} + \frac{8 x}{4}$

$y = - 4 + x$

Simplify the right side.

Simplify each term.

Divide $- 16$ by $4$ .

$y = - 4 + \frac{8 x}{4}$

$y = - 4 + x$

Cancel the common factor of $8$ and $4$ .

Factor $4$ out of $8 x$ .

$y = - 4 + \frac{4 (2 x)}{4}$

$y = - 4 + x$

Cancel the common factors.

Factor $4$ out of $4$ .

$y = - 4 + \frac{4 (2 x)}{4 (1)}$

$y = - 4 + x$

Cancel the common factor.

$y = - 4 + \frac{4 (2 x)}{4 \cdot 1}$

$y = - 4 + x$

Rewrite the expression.

$y = - 4 + \frac{2 x}{1}$

$y = - 4 + x$

Divide $2 x$ by $1$ .

$y = - 4 + 2 x$

$y = - 4 + x$

$y = - 4 + 2 x$

$y = - 4 + x$

$y = - 4 + 2 x$

$y = - 4 + x$

$y = - 4 + 2 x$

$y = - 4 + x$

$y = - 4 + 2 x$

$y = - 4 + x$

$y = - 4 + 2 x$

$y = - 4 + x$

Step 5

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(0, - 4)$

Step 6

Solve by Graphing 3x-3y=12 4y-8x=-16

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