Solve by Graphing 3x-4y=-12 , y=-3x+3

$3 x - 4 y = - 12$ , $y = - 3 x + 3$

Step 1

Subtract $3 x$ from both sides of the equation.

$- 4 y = - 12 - 3 x$

$y = - 3 x + 3$

Step 2

Divide each term in $- 4 y = - 12 - 3 x$ by $- 4$ and simplify.

Divide each term in $- 4 y = - 12 - 3 x$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{- 12}{- 4} + \frac{- 3 x}{- 4}$

$y = - 3 x + 3$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{- 12}{- 4} + \frac{- 3 x}{- 4}$

$y = - 3 x + 3$

Divide $y$ by $1$ .

$y = \frac{- 12}{- 4} + \frac{- 3 x}{- 4}$

$y = - 3 x + 3$

$y = \frac{- 12}{- 4} + \frac{- 3 x}{- 4}$

$y = - 3 x + 3$

$y = \frac{- 12}{- 4} + \frac{- 3 x}{- 4}$

$y = - 3 x + 3$

Simplify the right side.

Simplify each term.

Divide $- 12$ by $- 4$ .

$y = 3 + \frac{- 3 x}{- 4}$

$y = - 3 x + 3$

Dividing two negative values results in a positive value.

$y = 3 + \frac{3 x}{4}$

$y = - 3 x + 3$

$y = 3 + \frac{3 x}{4}$

$y = - 3 x + 3$

$y = 3 + \frac{3 x}{4}$

$y = - 3 x + 3$

$y = 3 + \frac{3 x}{4}$

$y = - 3 x + 3$

Step 3

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(0, 3)$

Step 4