Solve by Graphing 3x-y=-6 y=x+4

$3 x - y = - 6$ $y = x + 4$

Step 1

Subtract $3 x$ from both sides of the equation.

$- y = - 6 - 3 x$

$y = x + 4$

Step 2

Divide each term in $- y = - 6 - 3 x$ by $- 1$ and simplify.

Divide each term in $- y = - 6 - 3 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 6}{- 1} + \frac{- 3 x}{- 1}$

$y = x + 4$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 6}{- 1} + \frac{- 3 x}{- 1}$

$y = x + 4$

Divide $y$ by $1$ .

$y = \frac{- 6}{- 1} + \frac{- 3 x}{- 1}$

$y = x + 4$

$y = \frac{- 6}{- 1} + \frac{- 3 x}{- 1}$

$y = x + 4$

Simplify the right side.

Simplify each term.

Divide $- 6$ by $- 1$ .

$y = 6 + \frac{- 3 x}{- 1}$

$y = x + 4$

Move the negative one from the denominator of $\frac{- 3 x}{- 1}$ .

$y = 6 - 1 \cdot (- 3 x)$

$y = x + 4$

Rewrite $- 1 \cdot (- 3 x)$ as $- (- 3 x)$ .

$y = 6 - (- 3 x)$

$y = x + 4$

Multiply $- 3$ by $- 1$ .

$y = 6 + 3 x$

$y = x + 4$

$y = 6 + 3 x$

$y = x + 4$

$y = 6 + 3 x$

$y = x + 4$

$y = 6 + 3 x$

$y = x + 4$

Step 3

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(- 1, 3)$

Step 4