Solve by Graphing 4x-3y=-12 y=x+3

$4 x - 3 y = - 12$ $y = x + 3$

Subtract $4 x$ from both sides of the equation.

$- 3 y = - 12 - 4 x$

$y = x + 3$

Divide each term in $- 3 y = - 12 - 4 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = - 12 - 4 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{- 12}{- 3} + \frac{- 4 x}{- 3}$

$y = x + 3$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{- 12}{- 3} + \frac{- 4 x}{- 3}$

$y = x + 3$

Divide $y$ by $1$ .

$y = \frac{- 12}{- 3} + \frac{- 4 x}{- 3}$

$y = x + 3$

$y = \frac{- 12}{- 3} + \frac{- 4 x}{- 3}$

$y = x + 3$

$y = \frac{- 12}{- 3} + \frac{- 4 x}{- 3}$

$y = x + 3$

Simplify the right side.

Simplify each term.

Divide $- 12$ by $- 3$ .

$y = 4 + \frac{- 4 x}{- 3}$

$y = x + 3$

Dividing two negative values results in a positive value.

$y = 4 + \frac{4 x}{3}$

$y = x + 3$

$y = 4 + \frac{4 x}{3}$

$y = x + 3$

$y = 4 + \frac{4 x}{3}$

$y = x + 3$

$y = 4 + \frac{4 x}{3}$

$y = x + 3$

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(- 3, 0)$