Solve by Graphing 4x-3y=-4 , 2x-5y=-4

$4 x - 3 y = - 4$ , $2 x - 5 y = - 4$

Step 1

Subtract $4 x$ from both sides of the equation.

$- 3 y = - 4 - 4 x$

$2 x - 5 y = - 4$

Step 2

Divide each term in $- 3 y = - 4 - 4 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = - 4 - 4 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{- 4}{- 3} + \frac{- 4 x}{- 3}$

$2 x - 5 y = - 4$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{- 4}{- 3} + \frac{- 4 x}{- 3}$

$2 x - 5 y = - 4$

Divide $y$ by $1$ .

$y = \frac{- 4}{- 3} + \frac{- 4 x}{- 3}$

$2 x - 5 y = - 4$

$y = \frac{- 4}{- 3} + \frac{- 4 x}{- 3}$

$2 x - 5 y = - 4$

$y = \frac{- 4}{- 3} + \frac{- 4 x}{- 3}$

$2 x - 5 y = - 4$

Simplify the right side.

Simplify each term.

Dividing two negative values results in a positive value.

$y = \frac{4}{3} + \frac{- 4 x}{- 3}$

$2 x - 5 y = - 4$

Dividing two negative values results in a positive value.

$y = \frac{4}{3} + \frac{4 x}{3}$

$2 x - 5 y = - 4$

$y = \frac{4}{3} + \frac{4 x}{3}$

$2 x - 5 y = - 4$

$y = \frac{4}{3} + \frac{4 x}{3}$

$2 x - 5 y = - 4$

$y = \frac{4}{3} + \frac{4 x}{3}$

$2 x - 5 y = - 4$

Step 3

Subtract $2 x$ from both sides of the equation.

$- 5 y = - 4 - 2 x$

$y = \frac{4}{3} + \frac{4 x}{3}$

Step 4

Divide each term in $- 5 y = - 4 - 2 x$ by $- 5$ and simplify.

Divide each term in $- 5 y = - 4 - 2 x$ by $- 5$ .

$\frac{- 5 y}{- 5} = \frac{- 4}{- 5} + \frac{- 2 x}{- 5}$

$y = \frac{4}{3} + \frac{4 x}{3}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 y}{- 5} = \frac{- 4}{- 5} + \frac{- 2 x}{- 5}$

$y = \frac{4}{3} + \frac{4 x}{3}$

Divide $y$ by $1$ .

$y = \frac{- 4}{- 5} + \frac{- 2 x}{- 5}$

$y = \frac{4}{3} + \frac{4 x}{3}$

$y = \frac{- 4}{- 5} + \frac{- 2 x}{- 5}$

$y = \frac{4}{3} + \frac{4 x}{3}$

$y = \frac{- 4}{- 5} + \frac{- 2 x}{- 5}$

$y = \frac{4}{3} + \frac{4 x}{3}$

Simplify the right side.

Simplify each term.

Dividing two negative values results in a positive value.

$y = \frac{4}{5} + \frac{- 2 x}{- 5}$

$y = \frac{4}{3} + \frac{4 x}{3}$

Dividing two negative values results in a positive value.

$y = \frac{4}{5} + \frac{2 x}{5}$

$y = \frac{4}{3} + \frac{4 x}{3}$

$y = \frac{4}{5} + \frac{2 x}{5}$

$y = \frac{4}{3} + \frac{4 x}{3}$

$y = \frac{4}{5} + \frac{2 x}{5}$

$y = \frac{4}{3} + \frac{4 x}{3}$

$y = \frac{4}{5} + \frac{2 x}{5}$

$y = \frac{4}{3} + \frac{4 x}{3}$

Step 5

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(- \frac{4}{7}, \frac{4}{7})$

Step 6

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