Solve by Graphing 4x=y 2x^2-y=0

$4 x = y$ $2 x^{2} - y = 0$

Step 1

Rewrite the equation as $y = 4 x$ .

$y = 4 x$

$2 x^{2} - y = 0$

Step 2

Subtract $2 x^{2}$ from both sides of the equation.

$- y = - 2 x^{2}$

$y = 4 x$

Step 3

Divide each term in $- y = - 2 x^{2}$ by $- 1$ and simplify.

Divide each term in $- y = - 2 x^{2}$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 2 x^{2}}{- 1}$

$y = 4 x$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 2 x^{2}}{- 1}$

$y = 4 x$

Divide $y$ by $1$ .

$y = \frac{- 2 x^{2}}{- 1}$

$y = 4 x$

$y = \frac{- 2 x^{2}}{- 1}$

$y = 4 x$

Simplify the right side.

Move the negative one from the denominator of $\frac{- 2 x^{2}}{- 1}$ .

$y = - 1 \cdot (- 2 x^{2})$

$y = 4 x$

Rewrite $- 1 \cdot (- 2 x^{2})$ as $- (- 2 x^{2})$ .

$y = - (- 2 x^{2})$

$y = 4 x$

Multiply $- 2$ by $- 1$ .

$y = 2 x^{2}$

$y = 4 x$

$y = 2 x^{2}$

$y = 4 x$

$y = 2 x^{2}$

$y = 4 x$

Step 4

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(0, 0)$

$(2, 8)$

Step 5