Solve by Graphing 6x-3y=-9 and 2x+2y=-6

$6 x - 3 y = - 9$ and $2 x + 2 y = - 6$

Subtract $6 x$ from both sides of the equation.

$- 3 y = - 9 - 6 x$

$2 x + 2 y = - 6$

Divide each term in $- 3 y = - 9 - 6 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = - 9 - 6 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{- 9}{- 3} + \frac{- 6 x}{- 3}$

$2 x + 2 y = - 6$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{- 9}{- 3} + \frac{- 6 x}{- 3}$

$2 x + 2 y = - 6$

Divide $y$ by $1$ .

$y = \frac{- 9}{- 3} + \frac{- 6 x}{- 3}$

$2 x + 2 y = - 6$

$y = \frac{- 9}{- 3} + \frac{- 6 x}{- 3}$

$2 x + 2 y = - 6$

$y = \frac{- 9}{- 3} + \frac{- 6 x}{- 3}$

$2 x + 2 y = - 6$

Simplify the right side.

Simplify each term.

Divide $- 9$ by $- 3$ .

$y = 3 + \frac{- 6 x}{- 3}$

$2 x + 2 y = - 6$

Cancel the common factor of $- 6$ and $- 3$ .

Factor $- 3$ out of $- 6 x$ .

$y = 3 + \frac{- 3 (2 x)}{- 3}$

$2 x + 2 y = - 6$

Cancel the common factors.

Factor $- 3$ out of $- 3$ .

$y = 3 + \frac{- 3 (2 x)}{- 3 \cdot 1}$

$2 x + 2 y = - 6$

Cancel the common factor.

$y = 3 + \frac{- 3 (2 x)}{- 3 \cdot 1}$

$2 x + 2 y = - 6$

Rewrite the expression.

$y = 3 + \frac{2 x}{1}$

$2 x + 2 y = - 6$

Divide $2 x$ by $1$ .

$y = 3 + 2 x$

$2 x + 2 y = - 6$

$y = 3 + 2 x$

$2 x + 2 y = - 6$

$y = 3 + 2 x$

$2 x + 2 y = - 6$

$y = 3 + 2 x$

$2 x + 2 y = - 6$

$y = 3 + 2 x$

$2 x + 2 y = - 6$

$y = 3 + 2 x$

$2 x + 2 y = - 6$

Subtract $2 x$ from both sides of the equation.

$2 y = - 6 - 2 x$

$y = 3 + 2 x$

Divide each term in $2 y = - 6 - 2 x$ by $2$ and simplify.

Divide each term in $2 y = - 6 - 2 x$ by $2$ .

$\frac{2 y}{2} = \frac{- 6}{2} + \frac{- 2 x}{2}$

$y = 3 + 2 x$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{- 6}{2} + \frac{- 2 x}{2}$

$y = 3 + 2 x$

Divide $y$ by $1$ .

$y = \frac{- 6}{2} + \frac{- 2 x}{2}$

$y = 3 + 2 x$

$y = \frac{- 6}{2} + \frac{- 2 x}{2}$

$y = 3 + 2 x$

$y = \frac{- 6}{2} + \frac{- 2 x}{2}$

$y = 3 + 2 x$

Simplify the right side.

Simplify each term.

Divide $- 6$ by $2$ .

$y = - 3 + \frac{- 2 x}{2}$

$y = 3 + 2 x$

Cancel the common factor of $- 2$ and $2$ .

Factor $2$ out of $- 2 x$ .

$y = - 3 + \frac{2 (- x)}{2}$

$y = 3 + 2 x$

Cancel the common factors.

Factor $2$ out of $2$ .

$y = - 3 + \frac{2 (- x)}{2 (1)}$

$y = 3 + 2 x$

Cancel the common factor.

$y = - 3 + \frac{2 (- x)}{2 \cdot 1}$

$y = 3 + 2 x$

Rewrite the expression.

$y = - 3 + \frac{- x}{1}$

$y = 3 + 2 x$

Divide $- x$ by $1$ .

$y = - 3 - x$

$y = 3 + 2 x$

$y = - 3 - x$

$y = 3 + 2 x$

$y = - 3 - x$

$y = 3 + 2 x$

$y = - 3 - x$

$y = 3 + 2 x$

$y = - 3 - x$

$y = 3 + 2 x$

$y = - 3 - x$

$y = 3 + 2 x$

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(- 2, - 1)$

Solve by Graphing 6x-3y=-9 and 2x+2y=-6

Related Questions

Support LCMGCF.com by disabling your adblocker.