Solve by Graphing 9x-3y=18 , 3x=y+6

$9 x - 3 y = 18$ , $3 x = y + 6$

Step 1

Subtract $9 x$ from both sides of the equation.

$- 3 y = 18 - 9 x$

$3 x = y + 6$

Step 2

Divide each term in $- 3 y = 18 - 9 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = 18 - 9 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{18}{- 3} + \frac{- 9 x}{- 3}$

$3 x = y + 6$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{18}{- 3} + \frac{- 9 x}{- 3}$

$3 x = y + 6$

Divide $y$ by $1$ .

$y = \frac{18}{- 3} + \frac{- 9 x}{- 3}$

$3 x = y + 6$

$y = \frac{18}{- 3} + \frac{- 9 x}{- 3}$

$3 x = y + 6$

$y = \frac{18}{- 3} + \frac{- 9 x}{- 3}$

$3 x = y + 6$

Simplify the right side.

Simplify each term.

Divide $18$ by $- 3$ .

$y = - 6 + \frac{- 9 x}{- 3}$

$3 x = y + 6$

Cancel the common factor of $- 9$ and $- 3$ .

Factor $- 3$ out of $- 9 x$ .

$y = - 6 + \frac{- 3 (3 x)}{- 3}$

$3 x = y + 6$

Cancel the common factors.

Factor $- 3$ out of $- 3$ .

$y = - 6 + \frac{- 3 (3 x)}{- 3 \cdot 1}$

$3 x = y + 6$

Cancel the common factor.

$y = - 6 + \frac{- 3 (3 x)}{- 3 \cdot 1}$

$3 x = y + 6$

Rewrite the expression.

$y = - 6 + \frac{3 x}{1}$

$3 x = y + 6$

Divide $3 x$ by $1$ .

$y = - 6 + 3 x$

$3 x = y + 6$

$y = - 6 + 3 x$

$3 x = y + 6$

$y = - 6 + 3 x$

$3 x = y + 6$

$y = - 6 + 3 x$

$3 x = y + 6$

$y = - 6 + 3 x$

$3 x = y + 6$

$y = - 6 + 3 x$

$3 x = y + 6$

Step 3

Rewrite the equation as $y + 6 = 3 x$ .

$y + 6 = 3 x$

$y = - 6 + 3 x$

Step 4

Subtract $6$ from both sides of the equation.

$y = 3 x - 6$

$y = - 6 + 3 x$

Step 5

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

Always true

Step 6

Solve by Graphing 9x-3y=18 , 3x=y+6

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