Solve by Graphing -9x+3y=27 8x+8y=40

$- 9 x + 3 y = 27$ $8 x + 8 y = 40$

Step 1

Add $9 x$ to both sides of the equation.

$3 y = 27 + 9 x$

$8 x + 8 y = 40$

Step 2

Divide each term in $3 y = 27 + 9 x$ by $3$ and simplify.

Divide each term in $3 y = 27 + 9 x$ by $3$ .

$\frac{3 y}{3} = \frac{27}{3} + \frac{9 x}{3}$

$8 x + 8 y = 40$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{27}{3} + \frac{9 x}{3}$

$8 x + 8 y = 40$

Divide $y$ by $1$ .

$y = \frac{27}{3} + \frac{9 x}{3}$

$8 x + 8 y = 40$

$y = \frac{27}{3} + \frac{9 x}{3}$

$8 x + 8 y = 40$

$y = \frac{27}{3} + \frac{9 x}{3}$

$8 x + 8 y = 40$

Simplify the right side.

Simplify each term.

Divide $27$ by $3$ .

$y = 9 + \frac{9 x}{3}$

$8 x + 8 y = 40$

Cancel the common factor of $9$ and $3$ .

Factor $3$ out of $9 x$ .

$y = 9 + \frac{3 (3 x)}{3}$

$8 x + 8 y = 40$

Cancel the common factors.

Factor $3$ out of $3$ .

$y = 9 + \frac{3 (3 x)}{3 (1)}$

$8 x + 8 y = 40$

Cancel the common factor.

$y = 9 + \frac{3 (3 x)}{3 \cdot 1}$

$8 x + 8 y = 40$

Rewrite the expression.

$y = 9 + \frac{3 x}{1}$

$8 x + 8 y = 40$

Divide $3 x$ by $1$ .

$y = 9 + 3 x$

$8 x + 8 y = 40$

$y = 9 + 3 x$

$8 x + 8 y = 40$

$y = 9 + 3 x$

$8 x + 8 y = 40$

$y = 9 + 3 x$

$8 x + 8 y = 40$

$y = 9 + 3 x$

$8 x + 8 y = 40$

$y = 9 + 3 x$

$8 x + 8 y = 40$

Step 3

Subtract $8 x$ from both sides of the equation.

$8 y = 40 - 8 x$

$y = 9 + 3 x$

Step 4

Divide each term in $8 y = 40 - 8 x$ by $8$ and simplify.

Divide each term in $8 y = 40 - 8 x$ by $8$ .

$\frac{8 y}{8} = \frac{40}{8} + \frac{- 8 x}{8}$

$y = 9 + 3 x$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 y}{8} = \frac{40}{8} + \frac{- 8 x}{8}$

$y = 9 + 3 x$

Divide $y$ by $1$ .

$y = \frac{40}{8} + \frac{- 8 x}{8}$

$y = 9 + 3 x$

$y = \frac{40}{8} + \frac{- 8 x}{8}$

$y = 9 + 3 x$

$y = \frac{40}{8} + \frac{- 8 x}{8}$

$y = 9 + 3 x$

Simplify the right side.

Simplify each term.

Divide $40$ by $8$ .

$y = 5 + \frac{- 8 x}{8}$

$y = 9 + 3 x$

Cancel the common factor of $- 8$ and $8$ .

Factor $8$ out of $- 8 x$ .

$y = 5 + \frac{8 (- x)}{8}$

$y = 9 + 3 x$

Cancel the common factors.

Factor $8$ out of $8$ .

$y = 5 + \frac{8 (- x)}{8 (1)}$

$y = 9 + 3 x$

Cancel the common factor.

$y = 5 + \frac{8 (- x)}{8 \cdot 1}$

$y = 9 + 3 x$

Rewrite the expression.

$y = 5 + \frac{- x}{1}$

$y = 9 + 3 x$

Divide $- x$ by $1$ .

$y = 5 - x$

$y = 9 + 3 x$

$y = 5 - x$

$y = 9 + 3 x$

$y = 5 - x$

$y = 9 + 3 x$

$y = 5 - x$

$y = 9 + 3 x$

$y = 5 - x$

$y = 9 + 3 x$

$y = 5 - x$

$y = 9 + 3 x$

Step 5

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(- 1, 6)$

Step 6

Solve by Graphing -9x+3y=27 8x+8y=40

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