Solve by Graphing (x+2)^2-4=0

${(x + 2)}^{2} - 4 = 0$

Step 1

Simplify ${(x + 2)}^{2} - 4$ .

Simplify each term.

Rewrite ${(x + 2)}^{2}$ as $(x + 2) (x + 2)$ .

$(x + 2) (x + 2) - 4 = 0$

Expand $(x + 2) (x + 2)$ using the FOIL Method.

Apply the distributive property.

$x (x + 2) + 2 (x + 2) - 4 = 0$

Apply the distributive property.

$x \cdot x + x \cdot 2 + 2 (x + 2) - 4 = 0$

Apply the distributive property.

$x \cdot x + x \cdot 2 + 2 x + 2 \cdot 2 - 4 = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot 2 + 2 x + 2 \cdot 2 - 4 = 0$

Move $2$ to the left of $x$ .

$x^{2} + 2 \cdot x + 2 x + 2 \cdot 2 - 4 = 0$

Multiply $2$ by $2$ .

$x^{2} + 2 x + 2 x + 4 - 4 = 0$

Add $2 x$ and $2 x$ .

$x^{2} + 4 x + 4 - 4 = 0$

Combine the opposite terms in $x^{2} + 4 x + 4 - 4$ .

Subtract $4$ from $4$ .

$x^{2} + 4 x + 0 = 0$

Add $x^{2} + 4 x$ and $0$ .

$x^{2} + 4 x = 0$

Step 2

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x = - 4, 0$

Step 3