Solve by Graphing x+2y=-2 y=-1/3x

$x + 2 y = - 2$ $y = - \frac{1}{3} x$

Subtract $x$ from both sides of the equation.

$2 y = - 2 - x$

$y = - \frac{1}{3} x$

Divide each term in $2 y = - 2 - x$ by $2$ and simplify.

Divide each term in $2 y = - 2 - x$ by $2$ .

$\frac{2 y}{2} = \frac{- 2}{2} + \frac{- x}{2}$

$y = - \frac{1}{3} x$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{- 2}{2} + \frac{- x}{2}$

$y = - \frac{1}{3} x$

Divide $y$ by $1$ .

$y = \frac{- 2}{2} + \frac{- x}{2}$

$y = - \frac{1}{3} x$

$y = \frac{- 2}{2} + \frac{- x}{2}$

$y = - \frac{1}{3} x$

$y = \frac{- 2}{2} + \frac{- x}{2}$

$y = - \frac{1}{3} x$

Simplify the right side.

Simplify each term.

Divide $- 2$ by $2$ .

$y = - 1 + \frac{- x}{2}$

$y = - \frac{1}{3} x$

Move the negative in front of the fraction.

$y = - 1 - \frac{x}{2}$

$y = - \frac{1}{3} x$

$y = - 1 - \frac{x}{2}$

$y = - \frac{1}{3} x$

$y = - 1 - \frac{x}{2}$

$y = - \frac{1}{3} x$

$y = - 1 - \frac{x}{2}$

$y = - \frac{1}{3} x$

Combine $x$ and $\frac{1}{3}$ .

$y = - \frac{x}{3}$

$y = - 1 - \frac{x}{2}$

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(- 6, 2)$