Solve by Graphing x=4y x+2y=12

$x = 4 y$ $x + 2 y = 12$

Step 1

Rewrite the equation as $4 y = x$ .

$4 y = x$

$x + 2 y = 12$

Step 2

Divide each term in $4 y = x$ by $4$ and simplify.

Divide each term in $4 y = x$ by $4$ .

$\frac{4 y}{4} = \frac{x}{4}$

$x + 2 y = 12$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 y}{4} = \frac{x}{4}$

$x + 2 y = 12$

Divide $y$ by $1$ .

$y = \frac{x}{4}$

$x + 2 y = 12$

$y = \frac{x}{4}$

$x + 2 y = 12$

$y = \frac{x}{4}$

$x + 2 y = 12$

$y = \frac{x}{4}$

$x + 2 y = 12$

Step 3

Subtract $x$ from both sides of the equation.

$2 y = 12 - x$

$y = \frac{x}{4}$

Step 4

Divide each term in $2 y = 12 - x$ by $2$ and simplify.

Divide each term in $2 y = 12 - x$ by $2$ .

$\frac{2 y}{2} = \frac{12}{2} + \frac{- x}{2}$

$y = \frac{x}{4}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{12}{2} + \frac{- x}{2}$

$y = \frac{x}{4}$

Divide $y$ by $1$ .

$y = \frac{12}{2} + \frac{- x}{2}$

$y = \frac{x}{4}$

$y = \frac{12}{2} + \frac{- x}{2}$

$y = \frac{x}{4}$

$y = \frac{12}{2} + \frac{- x}{2}$

$y = \frac{x}{4}$

Simplify the right side.

Simplify each term.

Divide $12$ by $2$ .

$y = 6 + \frac{- x}{2}$

$y = \frac{x}{4}$

Move the negative in front of the fraction.

$y = 6 - \frac{x}{2}$

$y = \frac{x}{4}$

$y = 6 - \frac{x}{2}$

$y = \frac{x}{4}$

$y = 6 - \frac{x}{2}$

$y = \frac{x}{4}$

$y = 6 - \frac{x}{2}$

$y = \frac{x}{4}$

Step 5

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(8, 2)$

Step 6

Solve by Graphing x=4y x+2y=12

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