Solve by Graphing x-y=3 2x+y=5

$x - y = 3$ $2 x + y = 5$

Step 1

Subtract $x$ from both sides of the equation.

$- y = 3 - x$

$2 x + y = 5$

Step 2

Divide each term in $- y = 3 - x$ by $- 1$ and simplify.

Divide each term in $- y = 3 - x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{3}{- 1} + \frac{- x}{- 1}$

$2 x + y = 5$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{3}{- 1} + \frac{- x}{- 1}$

$2 x + y = 5$

Divide $y$ by $1$ .

$y = \frac{3}{- 1} + \frac{- x}{- 1}$

$2 x + y = 5$

$y = \frac{3}{- 1} + \frac{- x}{- 1}$

$2 x + y = 5$

Simplify the right side.

Simplify each term.

Divide $3$ by $- 1$ .

$y = - 3 + \frac{- x}{- 1}$

$2 x + y = 5$

Dividing two negative values results in a positive value.

$y = - 3 + \frac{x}{1}$

$2 x + y = 5$

Divide $x$ by $1$ .

$y = - 3 + x$

$2 x + y = 5$

$y = - 3 + x$

$2 x + y = 5$

$y = - 3 + x$

$2 x + y = 5$

$y = - 3 + x$

$2 x + y = 5$

Step 3

Subtract $2 x$ from both sides of the equation.

$y = 5 - 2 x$

$y = - 3 + x$

Step 4

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(\frac{8}{3}, - \frac{1}{3})$

Step 5