Solve by Graphing x-y=-4 , 3x+y=-4

$x - y = - 4$ , $3 x + y = - 4$

Step 1

Subtract $x$ from both sides of the equation.

$- y = - 4 - x$

$3 x + y = - 4$

Step 2

Divide each term in $- y = - 4 - x$ by $- 1$ and simplify.

Divide each term in $- y = - 4 - x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 4}{- 1} + \frac{- x}{- 1}$

$3 x + y = - 4$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 4}{- 1} + \frac{- x}{- 1}$

$3 x + y = - 4$

Divide $y$ by $1$ .

$y = \frac{- 4}{- 1} + \frac{- x}{- 1}$

$3 x + y = - 4$

$y = \frac{- 4}{- 1} + \frac{- x}{- 1}$

$3 x + y = - 4$

Simplify the right side.

Simplify each term.

Divide $- 4$ by $- 1$ .

$y = 4 + \frac{- x}{- 1}$

$3 x + y = - 4$

Dividing two negative values results in a positive value.

$y = 4 + \frac{x}{1}$

$3 x + y = - 4$

Divide $x$ by $1$ .

$y = 4 + x$

$3 x + y = - 4$

$y = 4 + x$

$3 x + y = - 4$

$y = 4 + x$

$3 x + y = - 4$

$y = 4 + x$

$3 x + y = - 4$

Step 3

Subtract $3 x$ from both sides of the equation.

$y = - 4 - 3 x$

$y = 4 + x$

Step 4

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(- 2, 2)$

Step 5