Solve by Graphing x+y=6 , 2x-y=3

$x + y = 6$ , $2 x - y = 3$

Step 1

Subtract $x$ from both sides of the equation.

$y = 6 - x$

$2 x - y = 3$

Step 2

Subtract $2 x$ from both sides of the equation.

$- y = 3 - 2 x$

$y = 6 - x$

Step 3

Divide each term in $- y = 3 - 2 x$ by $- 1$ and simplify.

Divide each term in $- y = 3 - 2 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{3}{- 1} + \frac{- 2 x}{- 1}$

$y = 6 - x$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{3}{- 1} + \frac{- 2 x}{- 1}$

$y = 6 - x$

Divide $y$ by $1$ .

$y = \frac{3}{- 1} + \frac{- 2 x}{- 1}$

$y = 6 - x$

$y = \frac{3}{- 1} + \frac{- 2 x}{- 1}$

$y = 6 - x$

Simplify the right side.

Simplify each term.

Divide $3$ by $- 1$ .

$y = - 3 + \frac{- 2 x}{- 1}$

$y = 6 - x$

Move the negative one from the denominator of $\frac{- 2 x}{- 1}$ .

$y = - 3 - 1 \cdot (- 2 x)$

$y = 6 - x$

Rewrite $- 1 \cdot (- 2 x)$ as $- (- 2 x)$ .

$y = - 3 - (- 2 x)$

$y = 6 - x$

Multiply $- 2$ by $- 1$ .

$y = - 3 + 2 x$

$y = 6 - x$

$y = - 3 + 2 x$

$y = 6 - x$

$y = - 3 + 2 x$

$y = 6 - x$

$y = - 3 + 2 x$

$y = 6 - x$

Step 4

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(3, 3)$

Step 5

Solve by Graphing x+y=6 , 2x-y=3

Related Questions

Support LCMGCF.com by disabling your adblocker.