Solve by Graphing y=-1/2x-3 , 4x-2y=16

$y = - \frac{1}{2} x - 3$ , $4 x - 2 y = 16$

Step 1

Combine $x$ and $\frac{1}{2}$ .

$y = - \frac{x}{2} - 3$

$4 x - 2 y = 16$

Step 2

Subtract $4 x$ from both sides of the equation.

$- 2 y = 16 - 4 x$

$y = - \frac{x}{2} - 3$

Step 3

Divide each term in $- 2 y = 16 - 4 x$ by $- 2$ and simplify.

Divide each term in $- 2 y = 16 - 4 x$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{16}{- 2} + \frac{- 4 x}{- 2}$

$y = - \frac{x}{2} - 3$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{16}{- 2} + \frac{- 4 x}{- 2}$

$y = - \frac{x}{2} - 3$

Divide $y$ by $1$ .

$y = \frac{16}{- 2} + \frac{- 4 x}{- 2}$

$y = - \frac{x}{2} - 3$

$y = \frac{16}{- 2} + \frac{- 4 x}{- 2}$

$y = - \frac{x}{2} - 3$

$y = \frac{16}{- 2} + \frac{- 4 x}{- 2}$

$y = - \frac{x}{2} - 3$

Simplify the right side.

Simplify each term.

Divide $16$ by $- 2$ .

$y = - 8 + \frac{- 4 x}{- 2}$

$y = - \frac{x}{2} - 3$

Cancel the common factor of $- 4$ and $- 2$ .

Factor $- 2$ out of $- 4 x$ .

$y = - 8 + \frac{- 2 (2 x)}{- 2}$

$y = - \frac{x}{2} - 3$

Cancel the common factors.

Factor $- 2$ out of $- 2$ .

$y = - 8 + \frac{- 2 (2 x)}{- 2 \cdot 1}$

$y = - \frac{x}{2} - 3$

Cancel the common factor.

$y = - 8 + \frac{- 2 (2 x)}{- 2 \cdot 1}$

$y = - \frac{x}{2} - 3$

Rewrite the expression.

$y = - 8 + \frac{2 x}{1}$

$y = - \frac{x}{2} - 3$

Divide $2 x$ by $1$ .

$y = - 8 + 2 x$

$y = - \frac{x}{2} - 3$

$y = - 8 + 2 x$

$y = - \frac{x}{2} - 3$

$y = - 8 + 2 x$

$y = - \frac{x}{2} - 3$

$y = - 8 + 2 x$

$y = - \frac{x}{2} - 3$

$y = - 8 + 2 x$

$y = - \frac{x}{2} - 3$

$y = - 8 + 2 x$

$y = - \frac{x}{2} - 3$

Step 4

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(2, - 4)$

Step 5

Solve by Graphing y=-1/2x-3 , 4x-2y=16

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