Solve by Graphing y=-1/2x+8 x-4y=-8

$y = - \frac{1}{2} x + 8$ $x - 4 y = - 8$

Combine $x$ and $\frac{1}{2}$ .

$y = - \frac{x}{2} + 8$

$x - 4 y = - 8$

Subtract $x$ from both sides of the equation.

$- 4 y = - 8 - x$

$y = - \frac{x}{2} + 8$

Divide each term in $- 4 y = - 8 - x$ by $- 4$ and simplify.

Divide each term in $- 4 y = - 8 - x$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{- 8}{- 4} + \frac{- x}{- 4}$

$y = - \frac{x}{2} + 8$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{- 8}{- 4} + \frac{- x}{- 4}$

$y = - \frac{x}{2} + 8$

Divide $y$ by $1$ .

$y = \frac{- 8}{- 4} + \frac{- x}{- 4}$

$y = - \frac{x}{2} + 8$

$y = \frac{- 8}{- 4} + \frac{- x}{- 4}$

$y = - \frac{x}{2} + 8$

$y = \frac{- 8}{- 4} + \frac{- x}{- 4}$

$y = - \frac{x}{2} + 8$

Simplify the right side.

Simplify each term.

Divide $- 8$ by $- 4$ .

$y = 2 + \frac{- x}{- 4}$

$y = - \frac{x}{2} + 8$

Dividing two negative values results in a positive value.

$y = 2 + \frac{x}{4}$

$y = - \frac{x}{2} + 8$

$y = 2 + \frac{x}{4}$

$y = - \frac{x}{2} + 8$

$y = 2 + \frac{x}{4}$

$y = - \frac{x}{2} + 8$

$y = 2 + \frac{x}{4}$

$y = - \frac{x}{2} + 8$

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(8, 4)$