Solve by Graphing y=-1/3x+2 y+4=-4/3x

$y = - \frac{1}{3} x + 2$ $y + 4 = - \frac{4}{3} x$

Step 1

Combine $x$ and $\frac{1}{3}$ .

$y = - \frac{x}{3} + 2$

$y + 4 = - \frac{4}{3} x$

Step 2

Simplify $- \frac{4}{3} x$ .

Rewrite.

$y + 4 = 0 + 0 - \frac{4}{3} x$

$y = - \frac{x}{3} + 2$

Simplify by adding zeros.

$y + 4 = - \frac{4}{3} x$

$y = - \frac{x}{3} + 2$

Combine $x$ and $\frac{4}{3}$ .

$y + 4 = - \frac{x \cdot 4}{3}$

$y = - \frac{x}{3} + 2$

Move $4$ to the left of $x$ .

$y + 4 = - \frac{4 x}{3}$

$y = - \frac{x}{3} + 2$

$y + 4 = - \frac{4 x}{3}$

$y = - \frac{x}{3} + 2$

Step 3

Subtract $4$ from both sides of the equation.

$y = - \frac{4 x}{3} - 4$

$y = - \frac{x}{3} + 2$

Step 4

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(- 6, 4)$

Step 5