Solve by Graphing y=2/3x+1 , y=-2/3x-1

$y = \frac{2}{3} x + 1$ , $y = - \frac{2}{3} x - 1$

Step 1

Combine $\frac{2}{3}$ and $x$ .

$y = \frac{2 x}{3} + 1$

$y = - \frac{2}{3} x - 1$

Step 2

Simplify each term.

Combine $x$ and $\frac{2}{3}$ .

$y = - \frac{x \cdot 2}{3} - 1$

$y = \frac{2 x}{3} + 1$

Move $2$ to the left of $x$ .

$y = - \frac{2 x}{3} - 1$

$y = \frac{2 x}{3} + 1$

$y = - \frac{2 x}{3} - 1$

$y = \frac{2 x}{3} + 1$

Step 3

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(- \frac{3}{2}, 0)$

Step 4