Solve by Graphing y=4-x , 2y=8-2x

$y = 4 - x$ , $2 y = 8 - 2 x$

Step 1

Reorder $4$ and $- x$ .

$y = - x + 4$

$2 y = 8 - 2 x$

Step 2

Divide each term in $2 y = 8 - 2 x$ by $2$ and simplify.

Divide each term in $2 y = 8 - 2 x$ by $2$ .

$\frac{2 y}{2} = \frac{8}{2} + \frac{- 2 x}{2}$

$y = - x + 4$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{8}{2} + \frac{- 2 x}{2}$

$y = - x + 4$

Divide $y$ by $1$ .

$y = \frac{8}{2} + \frac{- 2 x}{2}$

$y = - x + 4$

$y = \frac{8}{2} + \frac{- 2 x}{2}$

$y = - x + 4$

$y = \frac{8}{2} + \frac{- 2 x}{2}$

$y = - x + 4$

Simplify the right side.

Simplify each term.

Divide $8$ by $2$ .

$y = 4 + \frac{- 2 x}{2}$

$y = - x + 4$

Cancel the common factor of $- 2$ and $2$ .

Factor $2$ out of $- 2 x$ .

$y = 4 + \frac{2 (- x)}{2}$

$y = - x + 4$

Cancel the common factors.

Factor $2$ out of $2$ .

$y = 4 + \frac{2 (- x)}{2 (1)}$

$y = - x + 4$

Cancel the common factor.

$y = 4 + \frac{2 (- x)}{2 \cdot 1}$

$y = - x + 4$

Rewrite the expression.

$y = 4 + \frac{- x}{1}$

$y = - x + 4$

Divide $- x$ by $1$ .

$y = 4 - x$

$y = - x + 4$

$y = 4 - x$

$y = - x + 4$

$y = 4 - x$

$y = - x + 4$

$y = 4 - x$

$y = - x + 4$

$y = 4 - x$

$y = - x + 4$

$y = 4 - x$

$y = - x + 4$

Step 3

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

Always true

Step 4

Solve by Graphing y=4-x , 2y=8-2x

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