Solve by Graphing y=-4x+1 , 3y+12x=3

$y = - 4 x + 1$ , $3 y + 12 x = 3$

Step 1

Subtract $12 x$ from both sides of the equation.

$3 y = 3 - 12 x$

$y = - 4 x + 1$

Step 2

Divide each term in $3 y = 3 - 12 x$ by $3$ and simplify.

Divide each term in $3 y = 3 - 12 x$ by $3$ .

$\frac{3 y}{3} = \frac{3}{3} + \frac{- 12 x}{3}$

$y = - 4 x + 1$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{3}{3} + \frac{- 12 x}{3}$

$y = - 4 x + 1$

Divide $y$ by $1$ .

$y = \frac{3}{3} + \frac{- 12 x}{3}$

$y = - 4 x + 1$

$y = \frac{3}{3} + \frac{- 12 x}{3}$

$y = - 4 x + 1$

$y = \frac{3}{3} + \frac{- 12 x}{3}$

$y = - 4 x + 1$

Simplify the right side.

Simplify each term.

Divide $3$ by $3$ .

$y = 1 + \frac{- 12 x}{3}$

$y = - 4 x + 1$

Cancel the common factor of $- 12$ and $3$ .

Factor $3$ out of $- 12 x$ .

$y = 1 + \frac{3 (- 4 x)}{3}$

$y = - 4 x + 1$

Cancel the common factors.

Factor $3$ out of $3$ .

$y = 1 + \frac{3 (- 4 x)}{3 (1)}$

$y = - 4 x + 1$

Cancel the common factor.

$y = 1 + \frac{3 (- 4 x)}{3 \cdot 1}$

$y = - 4 x + 1$

Rewrite the expression.

$y = 1 + \frac{- 4 x}{1}$

$y = - 4 x + 1$

Divide $- 4 x$ by $1$ .

$y = 1 - 4 x$

$y = - 4 x + 1$

$y = 1 - 4 x$

$y = - 4 x + 1$

$y = 1 - 4 x$

$y = - 4 x + 1$

$y = 1 - 4 x$

$y = - 4 x + 1$

$y = 1 - 4 x$

$y = - 4 x + 1$

$y = 1 - 4 x$

$y = - 4 x + 1$

Step 3

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$y = - 4 x + 1$

Step 4

Solve by Graphing y=-4x+1 , 3y+12x=3

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