Solve by Graphing y+4x=8 , 5x+2y=13

$y + 4 x = 8$ , $5 x + 2 y = 13$

Step 1

Subtract $4 x$ from both sides of the equation.

$y = 8 - 4 x$

$5 x + 2 y = 13$

Step 2

Subtract $5 x$ from both sides of the equation.

$2 y = 13 - 5 x$

$y = 8 - 4 x$

Step 3

Divide each term in $2 y = 13 - 5 x$ by $2$ and simplify.

Divide each term in $2 y = 13 - 5 x$ by $2$ .

$\frac{2 y}{2} = \frac{13}{2} + \frac{- 5 x}{2}$

$y = 8 - 4 x$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{13}{2} + \frac{- 5 x}{2}$

$y = 8 - 4 x$

Divide $y$ by $1$ .

$y = \frac{13}{2} + \frac{- 5 x}{2}$

$y = 8 - 4 x$

$y = \frac{13}{2} + \frac{- 5 x}{2}$

$y = 8 - 4 x$

$y = \frac{13}{2} + \frac{- 5 x}{2}$

$y = 8 - 4 x$

Simplify the right side.

Move the negative in front of the fraction.

$y = \frac{13}{2} - \frac{5 x}{2}$

$y = 8 - 4 x$

$y = \frac{13}{2} - \frac{5 x}{2}$

$y = 8 - 4 x$

$y = \frac{13}{2} - \frac{5 x}{2}$

$y = 8 - 4 x$

Step 4

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(1, 4)$

Step 5