Solve by Graphing y=x^2-3x-4 x=y+8

$y = x^{2} - 3 x - 4$ $x = y + 8$

Step 1

Rewrite the equation as $y + 8 = x$ .

$y + 8 = x$

$y = x^{2} - 3 x - 4$

Step 2

Subtract $8$ from both sides of the equation.

$y = x - 8$

$y = x^{2} - 3 x - 4$

Step 3

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(2, - 6)$

Step 4