Solve by Graphing y=x^2-4 , x+y+2=0

$y = x^{2} - 4$ , $x + y + 2 = 0$

Step 1

Move all terms not containing $y$ to the right side of the equation.

Subtract $x$ from both sides of the equation.

$y + 2 = - x$

$y = x^{2} - 4$

Subtract $2$ from both sides of the equation.

$y = - x - 2$

$y = x^{2} - 4$

$y = - x - 2$

$y = x^{2} - 4$

Step 2

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(1, - 3)$

$(- 2, 0)$

Step 3