Solve by Graphing y=x^2 , y+4x=8

$y = x^{2}$ , $y + 4 x = 8$

Step 1

Subtract $4 x$ from both sides of the equation.

$y = 8 - 4 x$

$y = x^{2}$

Step 2

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(- 2 + 2 \sqrt{3}, 16 - 8 \sqrt{3})$

$(- 2 - 2 \sqrt{3}, 16 + 8 \sqrt{3})$

Step 3