Solve by Substitution 2x=16-8y x+4y=25

$2 x = 16 - 8 y$ $x + 4 y = 25$

Step 1

Divide each term in $2 x = 16 - 8 y$ by $2$ and simplify.

Divide each term in $2 x = 16 - 8 y$ by $2$ .

$\frac{2 x}{2} = \frac{16}{2} + \frac{- 8 y}{2}$

$x + 4 y = 25$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{16}{2} + \frac{- 8 y}{2}$

$x + 4 y = 25$

Divide $x$ by $1$ .

$x = \frac{16}{2} + \frac{- 8 y}{2}$

$x + 4 y = 25$

$x = \frac{16}{2} + \frac{- 8 y}{2}$

$x + 4 y = 25$

$x = \frac{16}{2} + \frac{- 8 y}{2}$

$x + 4 y = 25$

Simplify the right side.

Simplify each term.

Divide $16$ by $2$ .

$x = 8 + \frac{- 8 y}{2}$

$x + 4 y = 25$

Cancel the common factor of $- 8$ and $2$ .

Factor $2$ out of $- 8 y$ .

$x = 8 + \frac{2 (- 4 y)}{2}$

$x + 4 y = 25$

Cancel the common factors.

Factor $2$ out of $2$ .

$x = 8 + \frac{2 (- 4 y)}{2 (1)}$

$x + 4 y = 25$

Cancel the common factor.

$x = 8 + \frac{2 (- 4 y)}{2 \cdot 1}$

$x + 4 y = 25$

Rewrite the expression.

$x = 8 + \frac{- 4 y}{1}$

$x + 4 y = 25$

Divide $- 4 y$ by $1$ .

$x = 8 - 4 y$

$x + 4 y = 25$

$x = 8 - 4 y$

$x + 4 y = 25$

$x = 8 - 4 y$

$x + 4 y = 25$

$x = 8 - 4 y$

$x + 4 y = 25$

$x = 8 - 4 y$

$x + 4 y = 25$

$x = 8 - 4 y$

$x + 4 y = 25$

Step 2

Replace all occurrences of $x$ with $8 - 4 y$ in each equation.

Replace all occurrences of $x$ in $x + 4 y = 25$ with $8 - 4 y$ .

$(8 - 4 y) + 4 y = 25$

$x = 8 - 4 y$

Simplify the left side.

Combine the opposite terms in $(8 - 4 y) + 4 y$ .

Add $- 4 y$ and $4 y$ .

$8 + 0 = 25$

$x = 8 - 4 y$

Add $8$ and $0$ .

$8 = 25$

$x = 8 - 4 y$

$8 = 25$

$x = 8 - 4 y$

$8 = 25$

$x = 8 - 4 y$

$8 = 25$

$x = 8 - 4 y$

Step 3

Since $8 = 25$ is not true, there is no solution.

No solution

Step 4

Solve by Substitution 2x=16-8y x+4y=25

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