Solve by Substitution 2x-3y=-15 , x=4y

$2 x - 3 y = - 15$ , $x = 4 y$

Step 1

Replace all occurrences of $x$ with $4 y$ in each equation.

Replace all occurrences of $x$ in $2 x - 3 y = - 15$ with $4 y$ .

$2 (4 y) - 3 y = - 15$

$x = 4 y$

Simplify the left side.

Simplify $2 (4 y) - 3 y$ .

Multiply $4$ by $2$ .

$8 y - 3 y = - 15$

$x = 4 y$

Subtract $3 y$ from $8 y$ .

$5 y = - 15$

$x = 4 y$

$5 y = - 15$

$x = 4 y$

$5 y = - 15$

$x = 4 y$

$5 y = - 15$

$x = 4 y$

Step 2

Divide each term in $5 y = - 15$ by $5$ and simplify.

Divide each term in $5 y = - 15$ by $5$ .

$\frac{5 y}{5} = \frac{- 15}{5}$

$x = 4 y$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 y}{5} = \frac{- 15}{5}$

$x = 4 y$

Divide $y$ by $1$ .

$y = \frac{- 15}{5}$

$x = 4 y$

$y = \frac{- 15}{5}$

$x = 4 y$

$y = \frac{- 15}{5}$

$x = 4 y$

Simplify the right side.

Divide $- 15$ by $5$ .

$y = - 3$

$x = 4 y$

$y = - 3$

$x = 4 y$

$y = - 3$

$x = 4 y$

Step 3

Replace all occurrences of $y$ with $- 3$ in each equation.

Replace all occurrences of $y$ in $x = 4 y$ with $- 3$ .

$x = 4 (- 3)$

$y = - 3$

Simplify the right side.

Multiply $4$ by $- 3$ .

$x = - 12$

$y = - 3$

$x = - 12$

$y = - 3$

$x = - 12$

$y = - 3$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 12, - 3)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(- 12, - 3)$

Equation Form:

$x = - 12, y = - 3$

Step 6

Solve by Substitution 2x-3y=-15 , x=4y

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