Solve by Substitution 2x+3y=4 , 4x+6y=8

$2 x + 3 y = 4$ , $4 x + 6 y = 8$

Step 1

Solve for $x$ in $2 x + 3 y = 4$ .

Subtract $3 y$ from both sides of the equation.

$2 x = 4 - 3 y$

$4 x + 6 y = 8$

Divide each term in $2 x = 4 - 3 y$ by $2$ and simplify.

Divide each term in $2 x = 4 - 3 y$ by $2$ .

$\frac{2 x}{2} = \frac{4}{2} + \frac{- 3 y}{2}$

$4 x + 6 y = 8$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{4}{2} + \frac{- 3 y}{2}$

$4 x + 6 y = 8$

Divide $x$ by $1$ .

$x = \frac{4}{2} + \frac{- 3 y}{2}$

$4 x + 6 y = 8$

$x = \frac{4}{2} + \frac{- 3 y}{2}$

$4 x + 6 y = 8$

$x = \frac{4}{2} + \frac{- 3 y}{2}$

$4 x + 6 y = 8$

Simplify the right side.

Simplify each term.

Divide $4$ by $2$ .

$x = 2 + \frac{- 3 y}{2}$

$4 x + 6 y = 8$

Move the negative in front of the fraction.

$x = 2 - \frac{3 y}{2}$

$4 x + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

$4 x + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

$4 x + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

$4 x + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

$4 x + 6 y = 8$

Step 2

Replace all occurrences of $x$ with $2 - \frac{3 y}{2}$ in each equation.

Replace all occurrences of $x$ in $4 x + 6 y = 8$ with $2 - \frac{3 y}{2}$ .

$4 (2 - \frac{3 y}{2}) + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

Simplify the left side.

Simplify $4 (2 - \frac{3 y}{2}) + 6 y$ .

Simplify each term.

Apply the distributive property.

$4 \cdot 2 + 4 (- \frac{3 y}{2}) + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

Multiply $4$ by $2$ .

$8 + 4 (- \frac{3 y}{2}) + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{3 y}{2}$ into the numerator.

$8 + 4 (\frac{- 3 y}{2}) + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

Factor $2$ out of $4$ .

$8 + 2 (2) (\frac{- 3 y}{2}) + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

Cancel the common factor.

$8 + 2 \cdot (2 (\frac{- 3 y}{2})) + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

Rewrite the expression.

$8 + 2 (- 3 y) + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

$8 + 2 (- 3 y) + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

Multiply $- 3$ by $2$ .

$8 - 6 y + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

$8 - 6 y + 6 y = 8$

$x = 2 - \frac{3 y}{2}$

Combine the opposite terms in $8 - 6 y + 6 y$ .

Add $- 6 y$ and $6 y$ .

$8 + 0 = 8$

$x = 2 - \frac{3 y}{2}$

Add $8$ and $0$ .

$8 = 8$

$x = 2 - \frac{3 y}{2}$

$8 = 8$

$x = 2 - \frac{3 y}{2}$

$8 = 8$

$x = 2 - \frac{3 y}{2}$

$8 = 8$

$x = 2 - \frac{3 y}{2}$

$8 = 8$

$x = 2 - \frac{3 y}{2}$

Step 3

Remove any equations from the system that are always true.

$x = 2 - \frac{3 y}{2}$

Step 4

Solve by Substitution 2x+3y=4 , 4x+6y=8

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