Solve by Substitution 2x-y=23 and x-9=-1

$2 x - y = 23$ and $x - 9 = - 1$

Move all terms not containing $x$ to the right side of the equation.

Add $9$ to both sides of the equation.

$x = - 1 + 9$

$2 x - y = 23$

Add $- 1$ and $9$ .

$x = 8$

$2 x - y = 23$

$x = 8$

$2 x - y = 23$

Replace all occurrences of $x$ with $8$ in each equation.

Replace all occurrences of $x$ in $2 x - y = 23$ with $8$ .

$2 (8) - y = 23$

$x = 8$

Simplify the left side.

Multiply $2$ by $8$ .

$16 - y = 23$

$x = 8$

$16 - y = 23$

$x = 8$

$16 - y = 23$

$x = 8$

Solve for $y$ in $16 - y = 23$ .

Move all terms not containing $y$ to the right side of the equation.

Subtract $16$ from both sides of the equation.

$- y = 23 - 16$

$x = 8$

Subtract $16$ from $23$ .

$- y = 7$

$x = 8$

$- y = 7$

$x = 8$

Divide each term in $- y = 7$ by $- 1$ and simplify.

Divide each term in $- y = 7$ by $- 1$ .

$\frac{- y}{- 1} = \frac{7}{- 1}$

$x = 8$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{7}{- 1}$

$x = 8$

Divide $y$ by $1$ .

$y = \frac{7}{- 1}$

$x = 8$

$y = \frac{7}{- 1}$

$x = 8$

Simplify the right side.

Divide $7$ by $- 1$ .

$y = - 7$

$x = 8$

$y = - 7$

$x = 8$

$y = - 7$

$x = 8$

$y = - 7$

$x = 8$

Solve the system of equations $y = - 7 x = 8$ .

$y = - 7 x = 8$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(8, - 7)$

The result can be shown in multiple forms.

Point Form:

$(8, - 7)$

Equation Form:

$x = 8, y = - 7$

Solve by Substitution 2x-y=23 and x-9=-1

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