Solve by Substitution 2y=-2x+16 y-8=-x

$2 y = - 2 x + 16$ $y - 8 = - x$

Step 1

Divide each term in $2 y = - 2 x + 16$ by $2$ and simplify.

Divide each term in $2 y = - 2 x + 16$ by $2$ .

$\frac{2 y}{2} = \frac{- 2 x}{2} + \frac{16}{2}$

$y - 8 = - x$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{- 2 x}{2} + \frac{16}{2}$

$y - 8 = - x$

Divide $y$ by $1$ .

$y = \frac{- 2 x}{2} + \frac{16}{2}$

$y - 8 = - x$

$y = \frac{- 2 x}{2} + \frac{16}{2}$

$y - 8 = - x$

$y = \frac{- 2 x}{2} + \frac{16}{2}$

$y - 8 = - x$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 2$ and $2$ .

Factor $2$ out of $- 2 x$ .

$y = \frac{2 (- x)}{2} + \frac{16}{2}$

$y - 8 = - x$

Cancel the common factors.

Factor $2$ out of $2$ .

$y = \frac{2 (- x)}{2 (1)} + \frac{16}{2}$

$y - 8 = - x$

Cancel the common factor.

$y = \frac{2 (- x)}{2 \cdot 1} + \frac{16}{2}$

$y - 8 = - x$

Rewrite the expression.

$y = \frac{- x}{1} + \frac{16}{2}$

$y - 8 = - x$

Divide $- x$ by $1$ .

$y = - x + \frac{16}{2}$

$y - 8 = - x$

$y = - x + \frac{16}{2}$

$y - 8 = - x$

$y = - x + \frac{16}{2}$

$y - 8 = - x$

Divide $16$ by $2$ .

$y = - x + 8$

$y - 8 = - x$

$y = - x + 8$

$y - 8 = - x$

$y = - x + 8$

$y - 8 = - x$

$y = - x + 8$

$y - 8 = - x$

Step 2

Replace all occurrences of $y$ with $- x + 8$ in each equation.

Replace all occurrences of $y$ in $y - 8 = - x$ with $- x + 8$ .

$(- x + 8) - 8 = - x$

$y = - x + 8$

Simplify the left side.

Combine the opposite terms in $(- x + 8) - 8$ .

Subtract $8$ from $8$ .

$- x + 0 = - x$

$y = - x + 8$

Add $- x$ and $0$ .

$- x = - x$

$y = - x + 8$

$- x = - x$

$y = - x + 8$

$- x = - x$

$y = - x + 8$

$- x = - x$

$y = - x + 8$

Step 3

Remove any equations from the system that are always true.

$y = - x + 8$

Step 4

Solve by Substitution 2y=-2x+16 y-8=-x

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