Solve by Substitution -3x-3y=-12 y=0

$- 3 x - 3 y = - 12$ $y = 0$

Step 1

Replace all occurrences of $y$ with $0$ in each equation.

Replace all occurrences of $y$ in $- 3 x - 3 y = - 12$ with $0$ .

$- 3 x - 3 \cdot 0 = - 12$

$y = 0$

Simplify the left side.

Simplify $- 3 x - 3 \cdot 0$ .

Multiply $- 3$ by $0$ .

$- 3 x + 0 = - 12$

$y = 0$

Add $- 3 x$ and $0$ .

$- 3 x = - 12$

$y = 0$

$- 3 x = - 12$

$y = 0$

$- 3 x = - 12$

$y = 0$

$- 3 x = - 12$

$y = 0$

Step 2

Divide each term in $- 3 x = - 12$ by $- 3$ and simplify.

Divide each term in $- 3 x = - 12$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{- 12}{- 3}$

$y = 0$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{- 12}{- 3}$

$y = 0$

Divide $x$ by $1$ .

$x = \frac{- 12}{- 3}$

$y = 0$

$x = \frac{- 12}{- 3}$

$y = 0$

$x = \frac{- 12}{- 3}$

$y = 0$

Simplify the right side.

Divide $- 12$ by $- 3$ .

$x = 4$

$y = 0$

$x = 4$

$y = 0$

$x = 4$

$y = 0$

Step 3

Solve the system of equations $x = 4 y = 0$ .

$x = 4 y = 0$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(4, 0)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(4, 0)$

Equation Form:

$x = 4, y = 0$

Step 6

Solve by Substitution -3x-3y=-12 y=0

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