Solve by Substitution -3x+3y=4 y=x+3

$- 3 x + 3 y = 4$ $y = x + 3$

Step 1

Replace all occurrences of $y$ with $x + 3$ in each equation.

Replace all occurrences of $y$ in $- 3 x + 3 y = 4$ with $x + 3$ .

$- 3 x + 3 (x + 3) = 4$

$y = x + 3$

Simplify the left side.

Simplify $- 3 x + 3 (x + 3)$ .

Simplify each term.

Apply the distributive property.

$- 3 x + 3 x + 3 \cdot 3 = 4$

$y = x + 3$

Multiply $3$ by $3$ .

$- 3 x + 3 x + 9 = 4$

$y = x + 3$

$- 3 x + 3 x + 9 = 4$

$y = x + 3$

Simplify by adding terms.

Add $- 3 x$ and $3 x$ .

$0 + 9 = 4$

$y = x + 3$

Add $0$ and $9$ .

$9 = 4$

$y = x + 3$

$9 = 4$

$y = x + 3$

$9 = 4$

$y = x + 3$

$9 = 4$

$y = x + 3$

$9 = 4$

$y = x + 3$

Step 2

Since $9 = 4$ is not true, there is no solution.

No solution

Step 3

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