Solve by Substitution 3x+y=10 , y=2x

$3 x + y = 10$ , $y = 2 x$

Step 1

Replace all occurrences of $y$ with $2 x$ in each equation.

Replace all occurrences of $y$ in $3 x + y = 10$ with $2 x$ .

$3 x + 2 x = 10$

$y = 2 x$

Simplify the left side.

Simplify $3 x + 2 x$ .

Remove parentheses.

$3 x + 2 x = 10$

$y = 2 x$

Add $3 x$ and $2 x$ .

$5 x = 10$

$y = 2 x$

$5 x = 10$

$y = 2 x$

$5 x = 10$

$y = 2 x$

$5 x = 10$

$y = 2 x$

Step 2

Divide each term in $5 x = 10$ by $5$ and simplify.

Divide each term in $5 x = 10$ by $5$ .

$\frac{5 x}{5} = \frac{10}{5}$

$y = 2 x$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{10}{5}$

$y = 2 x$

Divide $x$ by $1$ .

$x = \frac{10}{5}$

$y = 2 x$

$x = \frac{10}{5}$

$y = 2 x$

$x = \frac{10}{5}$

$y = 2 x$

Simplify the right side.

Divide $10$ by $5$ .

$x = 2$

$y = 2 x$

$x = 2$

$y = 2 x$

$x = 2$

$y = 2 x$

Step 3

Replace all occurrences of $x$ with $2$ in each equation.

Replace all occurrences of $x$ in $y = 2 x$ with $2$ .

$y = 2 (2)$

$x = 2$

Simplify the right side.

Multiply $2$ by $2$ .

$y = 4$

$x = 2$

$y = 4$

$x = 2$

$y = 4$

$x = 2$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(2, 4)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(2, 4)$

Equation Form:

$x = 2, y = 4$

Step 6

Solve by Substitution 3x+y=10 , y=2x

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