Solve by Substitution 3x+y=10 , y=-3x+4

$3 x + y = 10$ , $y = - 3 x + 4$

Step 1

Replace all occurrences of $y$ with $- 3 x + 4$ in each equation.

Replace all occurrences of $y$ in $3 x + y = 10$ with $- 3 x + 4$ .

$3 x - 3 x + 4 = 10$

$y = - 3 x + 4$

Simplify the left side.

Simplify $3 x - 3 x + 4$ .

Remove parentheses.

$3 x - 3 x + 4 = 10$

$y = - 3 x + 4$

Subtract $3 x$ from $3 x$ .

$0 + 4 = 10$

$y = - 3 x + 4$

Add $0$ and $4$ .

$4 = 10$

$y = - 3 x + 4$

$4 = 10$

$y = - 3 x + 4$

$4 = 10$

$y = - 3 x + 4$

$4 = 10$

$y = - 3 x + 4$

Step 2

Since $4 = 10$ is not true, there is no solution.

No solution

Step 3

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