Solve by Substitution 3x+y=19 -6x-5=y

$3 x + y = 19$ $- 6 x - 5 = y$

Subtract $3 x$ from both sides of the equation.

$y = 19 - 3 x$

$- 6 x - 5 = y$

Replace all occurrences of $y$ with $19 - 3 x$ in each equation.

Replace all occurrences of $y$ in $- 6 x - 5 = y$ with $19 - 3 x$ .

$- 6 x - 5 = 19 - 3 x$

$y = 19 - 3 x$

Simplify the left side.

Remove parentheses.

$- 6 x - 5 = 19 - 3 x$

$y = 19 - 3 x$

$- 6 x - 5 = 19 - 3 x$

$y = 19 - 3 x$

$- 6 x - 5 = 19 - 3 x$

$y = 19 - 3 x$

Solve for $x$ in $- 6 x - 5 = 19 - 3 x$ .

Move all terms containing $x$ to the left side of the equation.

Add $3 x$ to both sides of the equation.

$- 6 x - 5 + 3 x = 19$

$y = 19 - 3 x$

Add $- 6 x$ and $3 x$ .

$- 3 x - 5 = 19$

$y = 19 - 3 x$

$- 3 x - 5 = 19$

$y = 19 - 3 x$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$- 3 x = 19 + 5$

$y = 19 - 3 x$

Add $19$ and $5$ .

$- 3 x = 24$

$y = 19 - 3 x$

$- 3 x = 24$

$y = 19 - 3 x$

Divide each term in $- 3 x = 24$ by $- 3$ and simplify.

Divide each term in $- 3 x = 24$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{24}{- 3}$

$y = 19 - 3 x$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{24}{- 3}$

$y = 19 - 3 x$

Divide $x$ by $1$ .

$x = \frac{24}{- 3}$

$y = 19 - 3 x$

$x = \frac{24}{- 3}$

$y = 19 - 3 x$

$x = \frac{24}{- 3}$

$y = 19 - 3 x$

Simplify the right side.

Divide $24$ by $- 3$ .

$x = - 8$

$y = 19 - 3 x$

$x = - 8$

$y = 19 - 3 x$

$x = - 8$

$y = 19 - 3 x$

$x = - 8$

$y = 19 - 3 x$

Replace all occurrences of $x$ with $- 8$ in each equation.

Replace all occurrences of $x$ in $y = 19 - 3 x$ with $- 8$ .

$y = 19 - 3 \cdot - 8$

$x = - 8$

Simplify the right side.

Simplify $19 - 3 \cdot - 8$ .

Multiply $- 3$ by $- 8$ .

$y = 19 + 24$

$x = - 8$

Add $19$ and $24$ .

$y = 43$

$x = - 8$

$y = 43$

$x = - 8$

$y = 43$

$x = - 8$

$y = 43$

$x = - 8$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 8, 43)$

The result can be shown in multiple forms.

Point Form:

$(- 8, 43)$

Equation Form:

$x = - 8, y = 43$

Solve by Substitution 3x+y=19 -6x-5=y

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