Solve by Substitution 3x+y=-3 , y=x+5

$3 x + y = - 3$ , $y = x + 5$

Step 1

Replace all occurrences of $y$ with $x + 5$ in each equation.

Replace all occurrences of $y$ in $3 x + y = - 3$ with $x + 5$ .

$3 x + x + 5 = - 3$

$y = x + 5$

Simplify the left side.

Simplify $3 x + x + 5$ .

Remove parentheses.

$3 x + x + 5 = - 3$

$y = x + 5$

Add $3 x$ and $x$ .

$4 x + 5 = - 3$

$y = x + 5$

$4 x + 5 = - 3$

$y = x + 5$

$4 x + 5 = - 3$

$y = x + 5$

$4 x + 5 = - 3$

$y = x + 5$

Step 2

Solve for $x$ in $4 x + 5 = - 3$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$4 x = - 3 - 5$

$y = x + 5$

Subtract $5$ from $- 3$ .

$4 x = - 8$

$y = x + 5$

$4 x = - 8$

$y = x + 5$

Divide each term in $4 x = - 8$ by $4$ and simplify.

Divide each term in $4 x = - 8$ by $4$ .

$\frac{4 x}{4} = \frac{- 8}{4}$

$y = x + 5$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{- 8}{4}$

$y = x + 5$

Divide $x$ by $1$ .

$x = \frac{- 8}{4}$

$y = x + 5$

$x = \frac{- 8}{4}$

$y = x + 5$

$x = \frac{- 8}{4}$

$y = x + 5$

Simplify the right side.

Divide $- 8$ by $4$ .

$x = - 2$

$y = x + 5$

$x = - 2$

$y = x + 5$

$x = - 2$

$y = x + 5$

$x = - 2$

$y = x + 5$

Step 3

Replace all occurrences of $x$ with $- 2$ in each equation.

Replace all occurrences of $x$ in $y = x + 5$ with $- 2$ .

$y = (- 2) + 5$

$x = - 2$

Simplify the right side.

Add $- 2$ and $5$ .

$y = 3$

$x = - 2$

$y = 3$

$x = - 2$

$y = 3$

$x = - 2$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 2, 3)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(- 2, 3)$

Equation Form:

$x = - 2, y = 3$

Step 6

Solve by Substitution 3x+y=-3 , y=x+5

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