Solve by Substitution 4x+4=y , y=6x

$4 x + 4 = y$ , $y = 6 x$

Step 1

Replace all occurrences of $y$ with $6 x$ in each equation.

Replace all occurrences of $y$ in $4 x + 4 = y$ with $6 x$ .

$4 x + 4 = 6 x$

$y = 6 x$

Simplify the left side.

Remove parentheses.

$4 x + 4 = 6 x$

$y = 6 x$

$4 x + 4 = 6 x$

$y = 6 x$

$4 x + 4 = 6 x$

$y = 6 x$

Step 2

Solve for $x$ in $4 x + 4 = 6 x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$4 x + 4 - 6 x = 0$

$y = 6 x$

Subtract $6 x$ from $4 x$ .

$- 2 x + 4 = 0$

$y = 6 x$

$- 2 x + 4 = 0$

$y = 6 x$

Subtract $4$ from both sides of the equation.

$- 2 x = - 4$

$y = 6 x$

Divide each term in $- 2 x = - 4$ by $- 2$ and simplify.

Divide each term in $- 2 x = - 4$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{- 4}{- 2}$

$y = 6 x$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{- 4}{- 2}$

$y = 6 x$

Divide $x$ by $1$ .

$x = \frac{- 4}{- 2}$

$y = 6 x$

$x = \frac{- 4}{- 2}$

$y = 6 x$

$x = \frac{- 4}{- 2}$

$y = 6 x$

Simplify the right side.

Divide $- 4$ by $- 2$ .

$x = 2$

$y = 6 x$

$x = 2$

$y = 6 x$

$x = 2$

$y = 6 x$

$x = 2$

$y = 6 x$

Step 3

Replace all occurrences of $x$ with $2$ in each equation.

Replace all occurrences of $x$ in $y = 6 x$ with $2$ .

$y = 6 (2)$

$x = 2$

Simplify the right side.

Multiply $6$ by $2$ .

$y = 12$

$x = 2$

$y = 12$

$x = 2$

$y = 12$

$x = 2$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(2, 12)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(2, 12)$

Equation Form:

$x = 2, y = 12$

Step 6

Solve by Substitution 4x+4=y , y=6x

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