Solve by Substitution -4x+7y+5=0 x-3y=-5

$- 4 x + 7 y + 5 = 0$ $x - 3 y = - 5$

Add $3 y$ to both sides of the equation.

$x = - 5 + 3 y$

$- 4 x + 7 y + 5 = 0$

Replace all occurrences of $x$ with $- 5 + 3 y$ in each equation.

Replace all occurrences of $x$ in $- 4 x + 7 y + 5 = 0$ with $- 5 + 3 y$ .

$- 4 (- 5 + 3 y) + 7 y + 5 = 0$

$x = - 5 + 3 y$

Simplify the left side.

Simplify $- 4 (- 5 + 3 y) + 7 y + 5$ .

Simplify each term.

Apply the distributive property.

$- 4 \cdot - 5 - 4 (3 y) + 7 y + 5 = 0$

$x = - 5 + 3 y$

Multiply $- 4$ by $- 5$ .

$20 - 4 (3 y) + 7 y + 5 = 0$

$x = - 5 + 3 y$

Multiply $3$ by $- 4$ .

$20 - 12 y + 7 y + 5 = 0$

$x = - 5 + 3 y$

$20 - 12 y + 7 y + 5 = 0$

$x = - 5 + 3 y$

Simplify by adding terms.

Add $20$ and $5$ .

$- 12 y + 7 y + 25 = 0$

$x = - 5 + 3 y$

Add $- 12 y$ and $7 y$ .

$- 5 y + 25 = 0$

$x = - 5 + 3 y$

$- 5 y + 25 = 0$

$x = - 5 + 3 y$

$- 5 y + 25 = 0$

$x = - 5 + 3 y$

$- 5 y + 25 = 0$

$x = - 5 + 3 y$

$- 5 y + 25 = 0$

$x = - 5 + 3 y$

Solve for $y$ in $- 5 y + 25 = 0$ .

Subtract $25$ from both sides of the equation.

$- 5 y = - 25$

$x = - 5 + 3 y$

Divide each term in $- 5 y = - 25$ by $- 5$ and simplify.

Divide each term in $- 5 y = - 25$ by $- 5$ .

$\frac{- 5 y}{- 5} = \frac{- 25}{- 5}$

$x = - 5 + 3 y$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 y}{- 5} = \frac{- 25}{- 5}$

$x = - 5 + 3 y$

Divide $y$ by $1$ .

$y = \frac{- 25}{- 5}$

$x = - 5 + 3 y$

$y = \frac{- 25}{- 5}$

$x = - 5 + 3 y$

$y = \frac{- 25}{- 5}$

$x = - 5 + 3 y$

Simplify the right side.

Divide $- 25$ by $- 5$ .

$y = 5$

$x = - 5 + 3 y$

$y = 5$

$x = - 5 + 3 y$

$y = 5$

$x = - 5 + 3 y$

$y = 5$

$x = - 5 + 3 y$

Replace all occurrences of $y$ with $5$ in each equation.

Replace all occurrences of $y$ in $x = - 5 + 3 y$ with $5$ .

$x = - 5 + 3 (5)$

$y = 5$

Simplify the right side.

Simplify $- 5 + 3 (5)$ .

Multiply $3$ by $5$ .

$x = - 5 + 15$

$y = 5$

Add $- 5$ and $15$ .

$x = 10$

$y = 5$

$x = 10$

$y = 5$

$x = 10$

$y = 5$

$x = 10$

$y = 5$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(10, 5)$

The result can be shown in multiple forms.

Point Form:

$(10, 5)$

Equation Form:

$x = 10, y = 5$

Solve by Substitution -4x+7y+5=0 x-3y=-5

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