Solve by Substitution 4x+y=32 , y=4x

$4 x + y = 32$ , $y = 4 x$

Step 1

Replace all occurrences of $y$ with $4 x$ in each equation.

Replace all occurrences of $y$ in $4 x + y = 32$ with $4 x$ .

$4 x + 4 x = 32$

$y = 4 x$

Simplify the left side.

Simplify $4 x + 4 x$ .

Remove parentheses.

$4 x + 4 x = 32$

$y = 4 x$

Add $4 x$ and $4 x$ .

$8 x = 32$

$y = 4 x$

$8 x = 32$

$y = 4 x$

$8 x = 32$

$y = 4 x$

$8 x = 32$

$y = 4 x$

Step 2

Divide each term in $8 x = 32$ by $8$ and simplify.

Divide each term in $8 x = 32$ by $8$ .

$\frac{8 x}{8} = \frac{32}{8}$

$y = 4 x$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 x}{8} = \frac{32}{8}$

$y = 4 x$

Divide $x$ by $1$ .

$x = \frac{32}{8}$

$y = 4 x$

$x = \frac{32}{8}$

$y = 4 x$

$x = \frac{32}{8}$

$y = 4 x$

Simplify the right side.

Divide $32$ by $8$ .

$x = 4$

$y = 4 x$

$x = 4$

$y = 4 x$

$x = 4$

$y = 4 x$

Step 3

Replace all occurrences of $x$ with $4$ in each equation.

Replace all occurrences of $x$ in $y = 4 x$ with $4$ .

$y = 4 (4)$

$x = 4$

Simplify the right side.

Multiply $4$ by $4$ .

$y = 16$

$x = 4$

$y = 16$

$x = 4$

$y = 16$

$x = 4$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(4, 16)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(4, 16)$

Equation Form:

$x = 4, y = 16$

Step 6

Solve by Substitution 4x+y=32 , y=4x

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