Solve by Substitution 4y+3=3y+x 2x+4y=18

$4 y + 3 = 3 y + x$ $2 x + 4 y = 18$

Solve for $y$ in $4 y + 3 = 3 y + x$ .

Move all terms containing $y$ to the left side of the equation.

Subtract $3 y$ from both sides of the equation.

$4 y + 3 - 3 y = x$

$2 x + 4 y = 18$

Subtract $3 y$ from $4 y$ .

$y + 3 = x$

$2 x + 4 y = 18$

$y + 3 = x$

$2 x + 4 y = 18$

Subtract $3$ from both sides of the equation.

$y = x - 3$

$2 x + 4 y = 18$

$y = x - 3$

$2 x + 4 y = 18$

Replace all occurrences of $y$ with $x - 3$ in each equation.

Replace all occurrences of $y$ in $2 x + 4 y = 18$ with $x - 3$ .

$2 x + 4 (x - 3) = 18$

$y = x - 3$

Simplify the left side.

Simplify $2 x + 4 (x - 3)$ .

Simplify each term.

Apply the distributive property.

$2 x + 4 x + 4 \cdot - 3 = 18$

$y = x - 3$

Multiply $4$ by $- 3$ .

$2 x + 4 x - 12 = 18$

$y = x - 3$

$2 x + 4 x - 12 = 18$

$y = x - 3$

Add $2 x$ and $4 x$ .

$6 x - 12 = 18$

$y = x - 3$

$6 x - 12 = 18$

$y = x - 3$

$6 x - 12 = 18$

$y = x - 3$

$6 x - 12 = 18$

$y = x - 3$

Solve for $x$ in $6 x - 12 = 18$ .

Move all terms not containing $x$ to the right side of the equation.

Add $12$ to both sides of the equation.

$6 x = 18 + 12$

$y = x - 3$

Add $18$ and $12$ .

$6 x = 30$

$y = x - 3$

$6 x = 30$

$y = x - 3$

Divide each term in $6 x = 30$ by $6$ and simplify.

Divide each term in $6 x = 30$ by $6$ .

$\frac{6 x}{6} = \frac{30}{6}$

$y = x - 3$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{30}{6}$

$y = x - 3$

Divide $x$ by $1$ .

$x = \frac{30}{6}$

$y = x - 3$

$x = \frac{30}{6}$

$y = x - 3$

$x = \frac{30}{6}$

$y = x - 3$

Simplify the right side.

Divide $30$ by $6$ .

$x = 5$

$y = x - 3$

$x = 5$

$y = x - 3$

$x = 5$

$y = x - 3$

$x = 5$

$y = x - 3$

Replace all occurrences of $x$ with $5$ in each equation.

Replace all occurrences of $x$ in $y = x - 3$ with $5$ .

$y = (5) - 3$

$x = 5$

Simplify the right side.

Subtract $3$ from $5$ .

$y = 2$

$x = 5$

$y = 2$

$x = 5$

$y = 2$

$x = 5$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(5, 2)$

The result can be shown in multiple forms.

Point Form:

$(5, 2)$

Equation Form:

$x = 5, y = 2$

Solve by Substitution 4y+3=3y+x 2x+4y=18

Related Questions

Support LCMGCF.com by disabling your adblocker.