Solve by Substitution -5x+2y=9 y=7x

$- 5 x + 2 y = 9$ $y = 7 x$

Replace all occurrences of $y$ with $7 x$ in each equation.

Replace all occurrences of $y$ in $- 5 x + 2 y = 9$ with $7 x$ .

$- 5 x + 2 (7 x) = 9$

$y = 7 x$

Simplify the left side.

Simplify $- 5 x + 2 (7 x)$ .

Multiply $7$ by $2$ .

$- 5 x + 14 x = 9$

$y = 7 x$

Add $- 5 x$ and $14 x$ .

$9 x = 9$

$y = 7 x$

$9 x = 9$

$y = 7 x$

$9 x = 9$

$y = 7 x$

$9 x = 9$

$y = 7 x$

Divide each term in $9 x = 9$ by $9$ and simplify.

Divide each term in $9 x = 9$ by $9$ .

$\frac{9 x}{9} = \frac{9}{9}$

$y = 7 x$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x}{9} = \frac{9}{9}$

$y = 7 x$

Divide $x$ by $1$ .

$x = \frac{9}{9}$

$y = 7 x$

$x = \frac{9}{9}$

$y = 7 x$

$x = \frac{9}{9}$

$y = 7 x$

Simplify the right side.

Divide $9$ by $9$ .

$x = 1$

$y = 7 x$

$x = 1$

$y = 7 x$

$x = 1$

$y = 7 x$

Replace all occurrences of $x$ with $1$ in each equation.

Replace all occurrences of $x$ in $y = 7 x$ with $1$ .

$y = 7 (1)$

$x = 1$

Simplify the right side.

Multiply $7$ by $1$ .

$y = 7$

$x = 1$

$y = 7$

$x = 1$

$y = 7$

$x = 1$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(1, 7)$

The result can be shown in multiple forms.

Point Form:

$(1, 7)$

Equation Form:

$x = 1, y = 7$

Solve by Substitution -5x+2y=9 y=7x

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