Solve by Substitution -5x-9y=33 -y-1=x

$- 5 x - 9 y = 33$ $- y - 1 = x$

Rewrite the equation as $x = - y - 1$ .

$x = - y - 1$

$- 5 x - 9 y = 33$

Replace all occurrences of $x$ with $- y - 1$ in each equation.

Replace all occurrences of $x$ in $- 5 x - 9 y = 33$ with $- y - 1$ .

$- 5 (- y - 1) - 9 y = 33$

$x = - y - 1$

Simplify the left side.

Simplify $- 5 (- y - 1) - 9 y$ .

Simplify each term.

Apply the distributive property.

$- 5 (- y) - 5 \cdot - 1 - 9 y = 33$

$x = - y - 1$

Multiply $- 1$ by $- 5$ .

$5 y - 5 \cdot - 1 - 9 y = 33$

$x = - y - 1$

Multiply $- 5$ by $- 1$ .

$5 y + 5 - 9 y = 33$

$x = - y - 1$

$5 y + 5 - 9 y = 33$

$x = - y - 1$

Subtract $9 y$ from $5 y$ .

$- 4 y + 5 = 33$

$x = - y - 1$

$- 4 y + 5 = 33$

$x = - y - 1$

$- 4 y + 5 = 33$

$x = - y - 1$

$- 4 y + 5 = 33$

$x = - y - 1$

Solve for $y$ in $- 4 y + 5 = 33$ .

Move all terms not containing $y$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$- 4 y = 33 - 5$

$x = - y - 1$

Subtract $5$ from $33$ .

$- 4 y = 28$

$x = - y - 1$

$- 4 y = 28$

$x = - y - 1$

Divide each term in $- 4 y = 28$ by $- 4$ and simplify.

Divide each term in $- 4 y = 28$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{28}{- 4}$

$x = - y - 1$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{28}{- 4}$

$x = - y - 1$

Divide $y$ by $1$ .

$y = \frac{28}{- 4}$

$x = - y - 1$

$y = \frac{28}{- 4}$

$x = - y - 1$

$y = \frac{28}{- 4}$

$x = - y - 1$

Simplify the right side.

Divide $28$ by $- 4$ .

$y = - 7$

$x = - y - 1$

$y = - 7$

$x = - y - 1$

$y = - 7$

$x = - y - 1$

$y = - 7$

$x = - y - 1$

Replace all occurrences of $y$ with $- 7$ in each equation.

Replace all occurrences of $y$ in $x = - y - 1$ with $- 7$ .

$x = - (- 7) - 1$

$y = - 7$

Simplify the right side.

Simplify $- (- 7) - 1$ .

Multiply $- 1$ by $- 7$ .

$x = 7 - 1$

$y = - 7$

Subtract $1$ from $7$ .

$x = 6$

$y = - 7$

$x = 6$

$y = - 7$

$x = 6$

$y = - 7$

$x = 6$

$y = - 7$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(6, - 7)$

The result can be shown in multiple forms.

Point Form:

$(6, - 7)$

Equation Form:

$x = 6, y = - 7$

Solve by Substitution -5x-9y=33 -y-1=x

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