Solve by Substitution 5y=10 x-3y=4

$5 y = 10$ $x - 3 y = 4$

Step 1

Divide each term in $5 y = 10$ by $5$ and simplify.

Divide each term in $5 y = 10$ by $5$ .

$\frac{5 y}{5} = \frac{10}{5}$

$x - 3 y = 4$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 y}{5} = \frac{10}{5}$

$x - 3 y = 4$

Divide $y$ by $1$ .

$y = \frac{10}{5}$

$x - 3 y = 4$

$y = \frac{10}{5}$

$x - 3 y = 4$

$y = \frac{10}{5}$

$x - 3 y = 4$

Simplify the right side.

Divide $10$ by $5$ .

$y = 2$

$x - 3 y = 4$

$y = 2$

$x - 3 y = 4$

$y = 2$

$x - 3 y = 4$

Step 2

Replace all occurrences of $y$ with $2$ in each equation.

Replace all occurrences of $y$ in $x - 3 y = 4$ with $2$ .

$x - 3 \cdot 2 = 4$

$y = 2$

Simplify the left side.

Multiply $- 3$ by $2$ .

$x - 6 = 4$

$y = 2$

$x - 6 = 4$

$y = 2$

$x - 6 = 4$

$y = 2$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $6$ to both sides of the equation.

$x = 4 + 6$

$y = 2$

Add $4$ and $6$ .

$x = 10$

$y = 2$

$x = 10$

$y = 2$

Step 4

Solve the system of equations $x = 10 y = 2$ .

$x = 10 y = 2$

Step 5

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(10, 2)$

Step 6

The result can be shown in multiple forms.

Point Form:

$(10, 2)$

Equation Form:

$x = 10, y = 2$

Step 7

Solve by Substitution 5y=10 x-3y=4

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