Solve by Substitution 8x+y=-16 , -3x+y=-5

$8 x + y = - 16$ , $- 3 x + y = - 5$

Step 1

Subtract $8 x$ from both sides of the equation.

$y = - 16 - 8 x$

$- 3 x + y = - 5$

Step 2

Replace all occurrences of $y$ with $- 16 - 8 x$ in each equation.

Replace all occurrences of $y$ in $- 3 x + y = - 5$ with $- 16 - 8 x$ .

$- 3 x - 16 - 8 x = - 5$

$y = - 16 - 8 x$

Simplify the left side.

Simplify $- 3 x - 16 - 8 x$ .

Remove parentheses.

$- 3 x - 16 - 8 x = - 5$

$y = - 16 - 8 x$

Subtract $8 x$ from $- 3 x$ .

$- 11 x - 16 = - 5$

$y = - 16 - 8 x$

$- 11 x - 16 = - 5$

$y = - 16 - 8 x$

$- 11 x - 16 = - 5$

$y = - 16 - 8 x$

$- 11 x - 16 = - 5$

$y = - 16 - 8 x$

Step 3

Solve for $x$ in $- 11 x - 16 = - 5$ .

Move all terms not containing $x$ to the right side of the equation.

Add $16$ to both sides of the equation.

$- 11 x = - 5 + 16$

$y = - 16 - 8 x$

Add $- 5$ and $16$ .

$- 11 x = 11$

$y = - 16 - 8 x$

$- 11 x = 11$

$y = - 16 - 8 x$

Divide each term in $- 11 x = 11$ by $- 11$ and simplify.

Divide each term in $- 11 x = 11$ by $- 11$ .

$\frac{- 11 x}{- 11} = \frac{11}{- 11}$

$y = - 16 - 8 x$

Simplify the left side.

Cancel the common factor of $- 11$ .

Cancel the common factor.

$\frac{- 11 x}{- 11} = \frac{11}{- 11}$

$y = - 16 - 8 x$

Divide $x$ by $1$ .

$x = \frac{11}{- 11}$

$y = - 16 - 8 x$

$x = \frac{11}{- 11}$

$y = - 16 - 8 x$

$x = \frac{11}{- 11}$

$y = - 16 - 8 x$

Simplify the right side.

Divide $11$ by $- 11$ .

$x = - 1$

$y = - 16 - 8 x$

$x = - 1$

$y = - 16 - 8 x$

$x = - 1$

$y = - 16 - 8 x$

$x = - 1$

$y = - 16 - 8 x$

Step 4

Replace all occurrences of $x$ with $- 1$ in each equation.

Replace all occurrences of $x$ in $y = - 16 - 8 x$ with $- 1$ .

$y = - 16 - 8 \cdot - 1$

$x = - 1$

Simplify the right side.

Simplify $- 16 - 8 \cdot - 1$ .

Multiply $- 8$ by $- 1$ .

$y = - 16 + 8$

$x = - 1$

Add $- 16$ and $8$ .

$y = - 8$

$x = - 1$

$y = - 8$

$x = - 1$

$y = - 8$

$x = - 1$

$y = - 8$

$x = - 1$

Step 5

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 1, - 8)$

Step 6

The result can be shown in multiple forms.

Point Form:

$(- 1, - 8)$

Equation Form:

$x = - 1, y = - 8$

Step 7

Solve by Substitution 8x+y=-16 , -3x+y=-5

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