Solve by Substitution -8x+y=-32 -3x-10=y

$- 8 x + y = - 32$ $- 3 x - 10 = y$

Step 1

Add $8 x$ to both sides of the equation.

$y = - 32 + 8 x$

$- 3 x - 10 = y$

Step 2

Replace all occurrences of $y$ with $- 32 + 8 x$ in each equation.

Replace all occurrences of $y$ in $- 3 x - 10 = y$ with $- 32 + 8 x$ .

$- 3 x - 10 = - 32 + 8 x$

$y = - 32 + 8 x$

Simplify the left side.

Remove parentheses.

$- 3 x - 10 = - 32 + 8 x$

$y = - 32 + 8 x$

$- 3 x - 10 = - 32 + 8 x$

$y = - 32 + 8 x$

$- 3 x - 10 = - 32 + 8 x$

$y = - 32 + 8 x$

Step 3

Solve for $x$ in $- 3 x - 10 = - 32 + 8 x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $8 x$ from both sides of the equation.

$- 3 x - 10 - 8 x = - 32$

$y = - 32 + 8 x$

Subtract $8 x$ from $- 3 x$ .

$- 11 x - 10 = - 32$

$y = - 32 + 8 x$

$- 11 x - 10 = - 32$

$y = - 32 + 8 x$

Move all terms not containing $x$ to the right side of the equation.

Add $10$ to both sides of the equation.

$- 11 x = - 32 + 10$

$y = - 32 + 8 x$

Add $- 32$ and $10$ .

$- 11 x = - 22$

$y = - 32 + 8 x$

$- 11 x = - 22$

$y = - 32 + 8 x$

Divide each term in $- 11 x = - 22$ by $- 11$ and simplify.

Divide each term in $- 11 x = - 22$ by $- 11$ .

$\frac{- 11 x}{- 11} = \frac{- 22}{- 11}$

$y = - 32 + 8 x$

Simplify the left side.

Cancel the common factor of $- 11$ .

Cancel the common factor.

$\frac{- 11 x}{- 11} = \frac{- 22}{- 11}$

$y = - 32 + 8 x$

Divide $x$ by $1$ .

$x = \frac{- 22}{- 11}$

$y = - 32 + 8 x$

$x = \frac{- 22}{- 11}$

$y = - 32 + 8 x$

$x = \frac{- 22}{- 11}$

$y = - 32 + 8 x$

Simplify the right side.

Divide $- 22$ by $- 11$ .

$x = 2$

$y = - 32 + 8 x$

$x = 2$

$y = - 32 + 8 x$

$x = 2$

$y = - 32 + 8 x$

$x = 2$

$y = - 32 + 8 x$

Step 4

Replace all occurrences of $x$ with $2$ in each equation.

Replace all occurrences of $x$ in $y = - 32 + 8 x$ with $2$ .

$y = - 32 + 8 (2)$

$x = 2$

Simplify the right side.

Simplify $- 32 + 8 (2)$ .

Multiply $8$ by $2$ .

$y = - 32 + 16$

$x = 2$

Add $- 32$ and $16$ .

$y = - 16$

$x = 2$

$y = - 16$

$x = 2$

$y = - 16$

$x = 2$

$y = - 16$

$x = 2$

Step 5

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(2, - 16)$

Step 6

The result can be shown in multiple forms.

Point Form:

$(2, - 16)$

Equation Form:

$x = 2, y = - 16$

Step 7

Solve by Substitution -8x+y=-32 -3x-10=y

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