Solve by Substitution x=-2 x+3y=4

$x = - 2$ $x + 3 y = 4$

Step 1

Replace all occurrences of $x$ with $- 2$ in each equation.

Replace all occurrences of $x$ in $x + 3 y = 4$ with $- 2$ .

$(- 2) + 3 y = 4$

$x = - 2$

Simplify the left side.

Remove parentheses.

$- 2 + 3 y = 4$

$x = - 2$

$- 2 + 3 y = 4$

$x = - 2$

$- 2 + 3 y = 4$

$x = - 2$

Step 2

Solve for $y$ in $- 2 + 3 y = 4$ .

Move all terms not containing $y$ to the right side of the equation.

Add $2$ to both sides of the equation.

$3 y = 4 + 2$

$x = - 2$

Add $4$ and $2$ .

$3 y = 6$

$x = - 2$

$3 y = 6$

$x = - 2$

Divide each term in $3 y = 6$ by $3$ and simplify.

Divide each term in $3 y = 6$ by $3$ .

$\frac{3 y}{3} = \frac{6}{3}$

$x = - 2$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{6}{3}$

$x = - 2$

Divide $y$ by $1$ .

$y = \frac{6}{3}$

$x = - 2$

$y = \frac{6}{3}$

$x = - 2$

$y = \frac{6}{3}$

$x = - 2$

Simplify the right side.

Divide $6$ by $3$ .

$y = 2$

$x = - 2$

$y = 2$

$x = - 2$

$y = 2$

$x = - 2$

$y = 2$

$x = - 2$

Step 3

Solve the system of equations $y = 2 x = - 2$ .

$y = 2 x = - 2$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 2, 2)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(- 2, 2)$

Equation Form:

$x = - 2, y = 2$

Step 6

Solve by Substitution x=-2 x+3y=4

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