Solve by Substitution x-2y=-1 3y=x+4

$x - 2 y = - 1$ $3 y = x + 4$

Step 1

Add $2 y$ to both sides of the equation.

$x = - 1 + 2 y$

$3 y = x + 4$

Step 2

Replace all occurrences of $x$ with $- 1 + 2 y$ in each equation.

Replace all occurrences of $x$ in $3 y = x + 4$ with $- 1 + 2 y$ .

$3 y = (- 1 + 2 y) + 4$

$x = - 1 + 2 y$

Simplify the right side.

Add $- 1$ and $4$ .

$3 y = 2 y + 3$

$x = - 1 + 2 y$

$3 y = 2 y + 3$

$x = - 1 + 2 y$

$3 y = 2 y + 3$

$x = - 1 + 2 y$

Step 3

Move all terms containing $y$ to the left side of the equation.

Subtract $2 y$ from both sides of the equation.

$3 y - 2 y = 3$

$x = - 1 + 2 y$

Subtract $2 y$ from $3 y$ .

$y = 3$

$x = - 1 + 2 y$

$y = 3$

$x = - 1 + 2 y$

Step 4

Replace all occurrences of $y$ with $3$ in each equation.

Replace all occurrences of $y$ in $x = - 1 + 2 y$ with $3$ .

$x = - 1 + 2 (3)$

$y = 3$

Simplify the right side.

Simplify $- 1 + 2 (3)$ .

Multiply $2$ by $3$ .

$x = - 1 + 6$

$y = 3$

Add $- 1$ and $6$ .

$x = 5$

$y = 3$

$x = 5$

$y = 3$

$x = 5$

$y = 3$

$x = 5$

$y = 3$

Step 5

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(5, 3)$

Step 6

The result can be shown in multiple forms.

Point Form:

$(5, 3)$

Equation Form:

$x = 5, y = 3$

Step 7

Solve by Substitution x-2y=-1 3y=x+4

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